MaplePrimes Questions

I am trying to use Markowitz theory to optimise a portfolio. At the moment I have got


> f := proc (x) options operator, arrow; piecewise(x = 1, 0.3e-2, x = 2, 0.4e-2, x = 3, 0.6e-2, x = 4, (-1)*0.6e-2, x = 5, 0.4e-2, x = 6, 0.1e-2, x = 7, 0.1e-2, x = 8, 0, x = 9, 0.4e-2, x = 10, 0.8e-2, x = 11, 0.6e-2, x = 12, 0.17e-1, x = 13, 0.2e-2, x = 14, 0.13e-1, x = 15, 0.12e-1, x = 16, 0.6e-2, x = 17, 0.1e-2, x = 18, 0.2e-2, x = 19, 0.1e-2, x = 20, 0.12e-1, x = 21, (-1...

Can someone send me a clear step by step instruction to install Maple 13 for 32 bit Linux?

My OS is Ubuntu 10.04 LTS netbook edition.

I don't want to install it in home folder,instead I want to create a folder(say,MAPLE) in a partition with a lot of space and then install Maple13 inside this folder.

I have a worksheet that contains various pieces of a robot's dynamic and kinematic equations.  I want to perform different design tasks, taking the base model and working off of it.  I'd like to have only 1 model of the robot and not duplicate it across all of my different design worksheets because things change in the robot model as I switch up tooling, find better means of performing a system identification, etc.

Is there any functionality that would allow...

These days I'm learning "maple introductory programming guide". About the command 'anames()',there is an example illustrated in the picture. I know anames(alluser) yields all the user-assigned names,including names containing a leading underscore ('_').

But I don't know why it yields the word "index/fill", can you tell me the meaning...



Dear Maple lovers,

As a classical worksheet user from the past years, now I'd like to be a "modern" Maple user, using the 2D Input in the modern worksheet mode (I will call it mwm from now on). But, alas, I cannot even solve a simple equation!

To describe my situation let me state the following:

1. I use 64 bit Maple 14 Student Edition (single user) under 64 bit Windows 7.

2....

how can i take any linear ode and make a plot of all its solutions, if its first order and second order?

thanks in advance

I All,

I just startup on Maple and i can't get the result of adding to  matrix. I used a worksheet and the math mode. The input is in 2-D Math Notation. Could Someone help me. 

> a := matrix([[93, 43], [19, 37]]); b := matrix([[48, 20], [19, 37]]);

> a+b;                             a + b

 

Thank You

I want to exactly (well roughly speaking) overlay two lines from different graphs. 

So suppose I had two datasets, 

a:=[1.4,2.1,4.6,3.7,3,2.1,2,1,1.5]:
b:=[78,75,97,98,105,95,88,75,67]:

with(plots):

aa:=listplot(a):
bb:=listplot(b):

I want to overlay the two lines to compare them.  I transformed them into 3d then rotated to overlay but maple keeps scaling the axes to fit. 

Any ideas?

 

I download a maple document from 'Recent Questions',"to find the constants of a equation with data x and y are given", then I open it, and click 'run all' comand in the toolbar. It works very well.

But when I put cursor in one line, and pree 'enter' key, it ruturns a different form of the result, as the picture above shows.

I have very simple equation for example

 

from equation   y=x+ex

we get the data     x :  1, 2, 3 , 4 ,5 , 6, 7 , 8 , 9 , 10

                           y :  3.7, 9.39, 23.09, 58.60, 153.41, 409.43, 1103.63, 2988.98, 8112.08, 22036.47

 

1) ...

I want to plot a piecewise function, F(x,y), so I look for piecewise command in help page, there are a lot of examples for one-variable piecewise functions, but lack of examples for two-variable piecewise functions. I don't know how to input a two-variable piecewise function and how to plot it, can you help me? Thank you very much.

 

Hi,

I am new to maple and this is my first question in this forum.

Please help me in finding an analytical solution to the 2nd order ode.

ode:=diff(y(x),x$2) -( a y(x) - y(x)^3 + y(x)^5 ) = 0

bcs:= D(y)(0) = 0, y(2) = 0, y(0) = 1.31

where a is a constant.

I am bit confused about the boundary conditions. I have three boundary conditions instead of two.

The first two boundary conditions yield trivial y(x) = 0 solution.so added the third bc.



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