ok so i have the differnetial equation

[latex] \lambda^{2} (\frac{dx}{dt})^{2} = (cos{ \alpha} - x)(cos{ \beta} - x) [/latex]

where [latex] x = cos{ \theta} [/latex]

and the solution is

[latex] x = cos{ \alpha} sin^{2}{\frac{t}{2 \lambda}} + cos{ \beta} cos^{2}{\frac{t}{2 \lambda}} [/latex]

please show you're working cos that's where im getting lost

now i want to use maple to show this is the solution to the eqn.

how do i do this???

Hi to all,

I need to verify an multivariate equality in maple, here it goes:

Nr := 3 - cos(x - y) - cos( z - x) - cos(y - z);

Dr := (sin(x/2))^2 +  (sin(y/2))^2 + (sin(z/2))^2;

assume(x>0, x<Pi); assume(y>0,y<Pi); assume(z>0,z<Pi);

eqn := Nr/Dr;

I need to check whether eqn <= 6. I have tried

is(eqn > 6)  and is(eqn <=6) and both give FAIL as output. But if I change the denominator, Dr say Dr := Dr + 6;

Dear all:

hi!

I am trying to solve an ODE for w(x);

E - a parameter
MI - a parameter
w(x) - Transverse deflection
q(x) - Transverse force on the beam with respect to x
G - a parameter
A - a parameter
ap - a parameter
si - a parameter
mysol1 - differential equation to be solved with boundary conditions (bc1,bc2,bc3 and bc4) applied

Hi everybody,

I have a symbolic matrix (11x11) it is sparsely populated with components on the diagonal and 2 places either side.  When I have tried to calculate the [standar operations > nverse] (on a PC with Raid 0 and 4 Gb) Maple 12 stops running at 1883 Mb and complains about 'memory allocation?

Q1: how do I (inexperienced maple user) increase memory allocation?

Q2: when I tried to run a 5x5 matrix as a test a matrix wasn't returned, only a list of letters?

like (1+x)(1+2x)^2=(1+x)(1+4x+4x^2)

I think people can do that with Mathematica

How to make Maple simplify expression like

sqrt(  x^(2*a+2) )

to x^(a+1), where x is assumed positive?

The Maple's simplify works only if the constant 'a' is already assigned to a number, otherwise it refuses to simplify it, even if I tell it assume(x>0).

Ok,

I have read the previous questions/answers regarding exporting a matrix to excel.  It is not working.

I am running Maple 10 Standard, XP, and Excel 2003.  I have Maple as an Add-In on Excel.

When I select my Matrix, right click, my options for export are:  MatLab, Tab Delimited, Matrix Market.  I chose Tab Delimited, but I get the same response from any choice, and an error box appears saying, "Error Fetching RTable ID".  Any suggestions?

Thanks

Hello,

I get an error message when I evaluate this line:

piecewise(And(And(abs(a)<infinity,a<>0),And(abs(b)<infinity,b<>0)),1,0);

Error, (in PDEtools/sort_as_in) sort: 2nd argument must be a function that always returns true or false

I don't know what the problem is with this line. I have Maple 12.

Have you got any idea?

How do I convert a 2D expression constructed with MathMLEditor to a normal 1 D string? I know that example 6 from the maplet builder tutorial does this, but the result is often in a prefix notation. For example, if I enter "x-square + 1" as a 2D expression in the MathMLEditor, the result is `&plus;`(x^2,1). I would like to get more normal x^2+1. I have examined the code generated by the maplet builder and experimented with options in the MathMLEditor and MathML[Import], but to no avail. Is there a way to convert the prefix notation to the more normal infix?

How do I simplify an expression imported from the MathMlEditor? For example, the following code is taken  from Maple help. I have saved the result in the variable abc.

with(Maplets[Elements]): maplet := Maplet([

    [BoxCell("Enter and expression")] , [MathMLEditor('reference'='ME1')],[Button("Done",Shutdown([ME1]))]  ]):

result := Maplets[Display](maplet): abc "= MathML[Import](result[1]);

Hello,

I am trying to assign a value to a variable depending on whether fsolve does or does not give a solution.

However, I cannot do it when there is no solution - fsolve returns unevaluated, and I cannot do almost anything with the unevaluated expression.

The only way I can do it is the following:

a:=fsolve(x+ln(x)=0,x=1..2);
if (a='fsolve(x+ln(x) = 0,x,1 .. 2)') then solution:='no' else solution:='yes' end if;

this equation does not have solutions, and returns the string to which I compare a.

Hi all

please help me to solve it

and give results please.......