Unanswered Questions

This page lists MaplePrimes questions that have not yet received an answer

hi,

how we can use maple to find solution of singuler integral equation by using product nystrom method or toeplitz method in maple?

I have the following expression (generated by some other procedure):

This does not have a taylor expansion in pV[6] in the general case because the square roots can become negative:

taylor(xpr,pV[6]);
Error, does not have a taylor expansion, try series()

But I can get an expansion by restrictig the range of pV[6]:

taylor(xpr,pV[6]) assuming -0.01<pV[6],pV[6]<0.01;

So far things are perfectly fine. But when I try mtaylor:

mtaylor(xpr,pV[6]) assuming -0.01<pV[6],pV[6]<0.01;
Error, (in assuming) when calling 'mtaylor'. Received: 'does not have a taylor expansion, try series()'

So the assumption seems to be ignored. I can work around this by expanding in pV[6] first, using taylor, and then expanding the result from that using mtaylor (I really also want the expansions in the other pV components; 6 in total although in this example some do not show up). I'll have to convince myself that this work-around gives the correct result but I think it does. However, I don't particularly like it.

I consider this a bug and am tempted to submit an SCR. But before I do that; is there anything obvious I am missing here?

Thanks,

M.D.

PS: This was done using Maple 15. I'll check newer versions later.

mtaylor_assuming.mw

Hello, when you run an error occurs:

Error, (in plots:-display) unknown plot object: circle
Error, (in plots:-display) expecting plot structure but received: P[0]
Error, (in plots:-display) expecting plot structure but received: PP

I'm not good in Maple. Please help me understand.

Programm: https://dropmefiles.com/Qnkzn

I attempted to show that two lines are parallel.  I started with a problem in Geometry for which I do not have the solution.

I tried several ways with Maple to show this to be true.  Most of the time, I ended when maple could not determine if a-b = c-d, etc.

brg_proof.txt contains a statement of the problem and my latest maple code.

Question: How should I approach the proof, by the compass and straight edge method?  Is this possible in maple?

I had a single variable equation but I do not know where variable y come from for using genus to run

I have problem to get real answer in a simple equation. maple just give me complex answer.

how i can get parametric real answer? Ihave trid this two way but not applicaple.

with(RealDomain); assume(T::real)

My code is:
Qz := 7.39833755306637215940309264474*10^7*sqrt(1/T)*(T-297.2)/T-16242.7935852035929839431551189*sqrt(1/T)/T;

q := (.6096*(299.2-T))/(sqrt(1.60000000000000000000000000000*10^(-9)-r^2)-0.346410161513775458705489268300e-4);

with(RealDomain); assume(T::real);

e := simplify(solve({0 = q-Qz}, {T}))

and the result like:

e := {T = 1/RootOf(-609600000000000000000000000000000000000000000000000000000+(879515018020273730453559011332895956000000000000000000000000000*sqrt(-625000000*r^2+1)-761682348615485390130551939524898425387968750740910059296172487)*Z^5+(-2959335021226548863761237057896000000000000000000000000000000*sqrt(-625000000*r^2+1)+2562859306691152293409465394507279449380503585614734443742000)*_Z^3+182392320000000000000000000000000000000000000000000000000000*_Z^2)^2}

dose anyone hase any opinion?

Why won't this procedure Compile? All I get is a cryptic and ungrammatical error message.

    step:= proc(
          n::integer[4],
          XYZ::Matrix(datatype= float[8]),
          E::Vector(datatype=integer[4]), F::Vector(datatype=integer[4]),
          W::Matrix(datatype= float[8]), #3x2 scratch matrix
          mu::integer[4]
     )
     option autocompile;
     local
          i::integer[4], j::integer[4],
          ed::float[8],
          fd::float[8],
          p::float[8], t::float[8]       
     ;
          to mu do
               for i to n do
                    ed:= 0;  fd:= 0;
                    for j to 3 do
                          p:= XYZ[i,j];
                          t:= XYZ[E[i],j] - p;
                          ed:= ed+t^2;
                          W[j,1]:= t;
                          t:= XYZ[F[i],j] - p;
                          fd:= fd+t^2;
                          W[j,2]:= t
                    od;
                    ed:= sqrt(ed) + .01;  fd:= sqrt(fd) + .01;
                    for j to 3 do
                         XYZ[i,j]:= 0.995*XYZ[i,j] - 0.01*W[j,1]/ed + 0.02*W[j,2]/fd
                    od
               od
          od
     end proc;
Compiler:-Compile(step);

Error, (in Compiler:-Compile1) In memory compilation failed

Hello guys,

I was just playing around with the Shanks transformation of a power series, when I noticed that polynomials aren't evaluated as I would expect.
I created this minimal working example; the function s should evaluate for z=0 to a[0], however it return simply 0.
Is there something I messed up?

restart

s := proc (n, z) options operator, arrow; sum(a[k]*z^k, k = 0 .. n) end proc;

proc (n, z) options operator, arrow; sum(a[k]*z^k, k = 0 .. n) end proc

(1)

series(s(n, z), z = 0)

series(a[0]+a[1]*z+a[2]*z^2+a[3]*z^3+a[4]*z^4+a[5]*z^5+O(z^6),z,6)

(2)

The value of s in z=0 should be a[0], however it returns 0:

s(n, 0)

0

(3)

s(1, 0)

0

(4)

Download evaluate_sum.mw

 

Thanks for your help,

Sören

 

Hi all,

 

It is believeble for me that the KummerU function is infinite or has a singular solution at r=0;

but without the command D(R) and dsolve ({er, D(R)(0)=0}, {R(r)}) that show the r=0 is a singular solution for the R(r), how could I prove it without using of these commands: for example is plotting of this function applicable??

while we have not the value of the  \lambda

````

restart

eq := diff(R(r), r, r)+(diff(R(r), r))/r+(-r^2+1)*lambda^2*R(r) = 0;

diff(diff(R(r), r), r)+(diff(R(r), r))/r+(-r^2+1)*lambda^2*R(r) = 0

(1)

``

dsolve(eq);

R(r) = _C1*exp(-(1/2)*lambda*r^2)*KummerM(1/2-(1/4)*lambda, 1, lambda*r^2)+_C2*exp(-(1/2)*lambda*r^2)*KummerU(1/2-(1/4)*lambda, 1, lambda*r^2)

(2)

``

dsolve({eq, (D(R))(0) = 0}, {R(r)})

R(r) = _C1*exp(-(1/2)*lambda*r^2)*KummerM(1/2-(1/4)*lambda, 1, lambda*r^2)

(3)

``````

``

``

``

R := proc (r) options operator, arrow; C1*exp(-(1/2)*lambda*r^2)*KummerM(1/2-(1/4)*lambda, 1, lambda*r^2)+_C2*exp(-(1/2)*lambda*r^2)*KummerU(1/2-(1/4)*lambda, 1, lambda*r^2) end proc

proc (r) options operator, arrow; C1*exp(-(1/2)*lambda*r^2)*KummerM(1/2-(1/4)*lambda, 1, lambda*r^2)+_C2*exp(-(1/2)*lambda*r^2)*KummerU(1/2-(1/4)*lambda, 1, lambda*r^2) end proc

(4)

``

``

``

D(R)

proc (r) options operator, arrow; -C1*lambda*r*exp(-(1/2)*lambda*r^2)*KummerM(1/2-(1/4)*lambda, 1, lambda*r^2)+2*C1*exp(-(1/2)*lambda*r^2)*((lambda*r^2-1/2-(1/4)*lambda)*KummerM(1/2-(1/4)*lambda, 1, lambda*r^2)+(1/2+(1/4)*lambda)*KummerM(-1/2-(1/4)*lambda, 1, lambda*r^2))/r-_C2*lambda*r*exp(-(1/2)*lambda*r^2)*KummerU(1/2-(1/4)*lambda, 1, lambda*r^2)+2*_C2*exp(-(1/2)*lambda*r^2)*((lambda*r^2-1/2-(1/4)*lambda)*KummerU(1/2-(1/4)*lambda, 1, lambda*r^2)-KummerU(-1/2-(1/4)*lambda, 1, lambda*r^2))/r end proc

(5)

``

``


Download Kummer.mwKummer.mw

                         

         
               

Hi all, 

Is it possible, and how, to disable the automatic completion in the "Advanced Search / keyword" field ?

Underlying this question is my looking for informations about cmaple (beyond what the help page displays : if I can't find any I will ask some specific ones later). But every time I type "cmaple" in the keyword textfield, it is replaced by "campée" (which is a french word ... I guess english people will obtain something different)

I would like the C-Text style in 14pt Times Roman while the C-2D-Math style is 12pt.

My use case is that I am typing in a single execution block.

I use Format >> Styles and select the style for C-Text and set it to 14pt Times. I click OK to close the dialog. Next I repeat this for the C-2D-Math style but this time set the font size to 12pt and, for testing, the colour to blue. The effect is to give me 14pt Times for both styles, though the C-text is black and the 2-D-Math is blue.

Can the effect I want be achieved, or is this a bug/feature?

This is Maple 2016.1 on Windows 10 64bit

 Thanks for any help

Hi everyone.

I'm going to solve a problem with HPM in Maple. I wrote some initial codes but now I'm confused becouse of P^0 coefficients in A1 and B1. I mean I can't reach to f0 and g0.

I upload that file. these are codes that i typed. could you please help me how can I reach to them(f0 & g0)?

http://www.filehosting.org/file/details/573095/Maple%20Project+.mw

Hi all,

Using the Physics package, I have defined a density operator, shown in the image below:

Definition of Density Operator

(I did assume(s ≠i), assume(v≠h).

I then operate on it with the Bracket as shown in the next image:

Bracket on Density Operator

 

I think this should evaluate to (|Y,s,h><Y,s,h|)/2; or at least that's the result I want. However, Maple evaluates this to zero.

Is there a where to convince Maple to evaluate this to what I want/expect?

Thanks in advance,

Kevin

why the current luca_amplificatore_retroazione.msimand voltage is egual to zero?

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