In order to make worksheets more interactive in a teaching environment I have begun playing around with the Tables the standard GUI provides. The idea is that in the left column is the script we are working through while in the right column is space a student can work with the equations and formulae from the left side to, e.g., plot, change parameters etc. without affecting the script too much.

To build the tables I copy-pasted code from a normal worksheet (in document mode) into the left column, creating rows of appropriate length to have a logically coherent section in one row. Usually one row is one Section (in the technical sense of Maple Sections). The student gets to play in the right column.

In principle this seems to work quite well in my preliminary testing. I did find out rather quickly that on the right side one needs to be in 1-d input mode with a prompt for anything to be calculated interactively. Ok, actually probably easier to do. The table is set to evaluate by row so the right-left correspondence is preserved.

A potential issue I am facing however is with equation numbering: I use equation numbers extensively to reference back to upstream results. In the Table, it appears that equation numbers are not unique; in each row of the Table, eq. numbers start as (1.1), (1.2) etc. I am able to reference back to results from a prior row, even though the same equation number will show up again later in the new row. But I am concerned that eventually this all ends up in a big mess and my references point to the wrong expression or equation. Non-unique line numbers seem like a Really Bad Idea, and I'd like to avoid that if possible.

Does anyone know how the lines numbers work for code in Tables and how I make sure they are unique? I suppose I could explicitly assign results I need in other rows to names, but that does not prevent a reference to an eq. number from pulling in the wrong one from a prior row (assuming for the moment that Maple will never look forward to resolve a reference).

Thanks,

Mac Dude

Can someone help me to solve system of equations please. I have a system of 8 complex valued equations, with 8 unknowns: _C1,_C2........_C8

Equation system looks like:

eq_system:={ -3.248046797 10 _C1 + 1.773373463 10 _C2 + (2.182313824 10 - 9.987524076 10 I) _C3 + 1.773373463 10 _C4 = -7.389056097 10 _C2- 7.389056097 10 _C4+ (4.161468365 10 + 9.092974265 10 I)_C3,

............}  its only 1st equation, others are similar.

It looks rather simple though I am not able to solve it with solve or fsolve commands. What I'm doing wrong?

solve(eq_system,{_C1,_C2,_C3,_C4,_C5,_C6,_C7,_C8});

I'm trying to interpolate values using spline (data,x,degrees=2).

So I'm setting curvefit:=spline(data,x,degrees=2);

fsolve(curvefit=4,x);

However, I'm trying to solve this over a range of values in matrix M:=1..2000;

I'm sifting through the online documentation, but I can't find a proper way to do this. Ideally, i'd want to store the results as a seperate matrix.

Hi,

I have a code compute some function : 

         alpha1:(n, m,1) -> (n + 1) (int(K(|m h - y|), y = n h .. (n + 1) h))

              int(K(|m h - y|) y, y = n h .. (n + 1) h)
            - -----------------------------------------
                                  h                    
         alpha2:  (n, m,2) -> -n (int(K(|m h - y|), y = n h .. (n + 1) h))

                int(K(|m h - y|) y, y = n h .. (n + 1) h)
              + -----------------------------------------
                                    h                    
and  I have a Matrix "MatA" .

My aim, when I give the value of the Kernel K used in alpha1, and alpha2, like K(x,y)=ln|x-y| , I want a numerci Matrix.

How can I do it.

Many thinks.

Fred.mw

How do I find the constants in a solution containing whittaker functions?

the boundary conditions are:

c(x,0)=1

c(0,y)=1

[c'(1,y),x]=0

Sorry if this has been already posted.

When print() is invoked from a proc into a module, non-English characters are not properly displayed with Maple 18.

It works ok if it is invoked from within the workbook.

Example:
print("Están en perspectiva")

Put this sentence in a proc into a module and the character "á" wont be displayed

Output: "Est�n en perspectiva"

Any hint about how to treat this issue?

Thank you very much.

César Lozada 

So im trying to write a maple script that computes the Jordan form of a given (3x3)- matrix
A. If {a,b,c} is a basis with respect to which A is in Jordan form, then I'm trying to make it
plot the three lines spanned by a, b and c, in the standard coordinate system. I was hinted to use plot3d here.

sidenote: I know how to compute the jordan matrix of A, such by find the eigen vectors and generalised eigen vectors and putting them in as columns in a 3x3 matrix say S,   where S is invertible    then  (S^-1)*(A)*(S) = (J).

Thanks in advance. <3

Hi:

i follow the code newton raphson for solve system nonlinear ODE in maple,every body have code for it?

When creating questions with Question Designer, how can I include notes that are visible to instructors only? I don't want students to see certain info. Is it in the "information fields"?   

I have a worksheet. I edit some variables' value. I then execute the whole worksheet to see how the graphs change. But the graphs generated by display command do not appear. All other calculations update fine. 

To overcome this. I save worksheet with my new variable values. Close the worksheet. Reopen it. Execute it. And now the graphs appear fine.

 I have a complex set of mechanical linkages and components, and I am trying to create a feedback control system for trajectory-tracking with the end-effector. They system is driven by a set of prismatic joints (representing ideal series-elastic actuators). At this stage I am simply trying to establish the control parameters and the required forces to achieve desired positions/velocities in the workspace, and have not yet inserted any realistic actuator characteristics.

An open-loop solution can be found using translational position control on the prismatic joints, this is no problem. However to close the loop properly, I need to convert the system to use a differential input, such as a velocity driver. At this point everything becomes very finicky and highly dependent on initial conditions. Generally Maplesim gives up, claiming that no solution can be found. Due to the complexity of the system, there is no way for me to guess a priori the appropriate initial conditions of all the joints and linkages. I was wondering if anybody had any tips for either pre-determining the initial parameters, or alternatively for relaxing the solver in some way to allow for a wider exploration of possible solutions. Or any other ideas!

So far: I have tried setting up an open loop position-driven system with the same trajectories and using Maple to read all the initial conditions, then transferring them as guesses to my closed-loop system. But this has not worked. As a temporary workaround I am using position drivers on the SEAs, which are in turn driven by a velocity controller (with an integrator term). However this is suboptimal. Any help would be much appreciated!

I  often find mself in the following quandry: I am investigating a problem, I do a few examples, run a do loop for j from1 to 5 to see if that works and then enter

for j from 1 to 200 do  a[j]:=blah, blah,...  end do:

and 15 minutes later nothing has happened. Is the loop finishing up with j = 198 or so or is it stuck at j = 23 and it will take forever to finish? Or perhaps there is an error that turns up for j > 23?

When I think about it I can insert a print(j) command to keep track of this but there are other situations where that doesn't work. For example,

Order := 35; mtaylor(....

When nothing happens is that because the calculation is almost done? or stuck? etc.

Is it possible to take a quick peek at the state of Maple and the decide whtether to continue the computation or abort? If the calculation of mtaylor(... is particularly long I might settle for the 15 coeficients computed so far rather than abort. Can I get at those?

Any advice?

Using the Fourier convolution theorem to solve f(t) =sin (t)

f(t)=R dJ(t)/dt+J(t)/C

Hi,

When I run two times my code, the results change.

Have you any idea, why???