## 50 Reputation

1 years, 135 days

## Rf...

@Carl Love Dear sir, i already find the solution by using fsolve and newton method but i am interested to find to by using Regula falsi method, pls correct me where is the problem, why it is not giving result. By the wan can you explain this command why you did this, what does it means?

`d:= ilog10(op(1,r));`

## need expression or polynomial...

@Preben Alsholm sir basically i need an expression in terms of sigma when pg1=0 to use in another expression so that is why I am using fsolve or considering numeric values or we should construct a polynomial of an expression fter obtaining pg1=0 for different value of k and q, but the problem is  how to construct a polynomial for sigma in term of lamda for fix value of k and Q by using fitting curve command....sorry i am no to good in maple

## need expression...

@Kitonum sir basically i need an expression in terms of sigma when pg1=0 to use in another expression so that is why I am using fsolve or considering numeric values

## @Preben Alsholm  it is working only...

@Preben Alsholm  it is working only when n=1 but could not get the answer when n greater then 1

@Preben Alsholm sir can you pls did the same thing in my worksheet that i already attached because i am applying this command but could not getting the answer

## plot...

@tomleslie Thank you for our time and is there any option to convert original ODE Into a set of the first-order ode by using commands and how to plot the final result if the value of epsilon in numerator A and in denominator  =B for different value of  A and B.

sir one more thing how can i apply perturbation method on the same problem?

## @Carl Love yes, you are write ...

@Carl Love yes, you are write  the original Equation is 2d order ode. as now i want to calculate the value of both involved constant of integration that is A and C1 by using the given both boudary condition

## Thanks...

@vv with due respect we already follow the same procedure to draw these type of graph and we call this graph streamline graph and they have alot sense to us. i just change the basic equation to draw but faceing issue

## complete file...

@acer dear sir please a complete file, actually i want to plot  please have a look on my file

complete.mw

## Example...

@vv sir please a look on attached file. I need an expression like in attached file......in this file v is also a function of both x and y

Example_Int.mw

## Thanks...

@vv sir i already compute  an expression for v which contain both x and y, i need an expression for v to use another place, i do need required its numeric value

## arrow...

@Kitonum sir is there any method put upward arrow or downward arow through command like we put legends?

## subscript...

@Kitonum  Dear sir you did a lot for me i learn too much from you but still have two issues about plotting

1- how to write subscript in legends i am trying by putting Q[1]=0.5 but fail?

2. if the line of the graph are two close and want to observe the behaviour of the graph and need to add a picture of a specific area as a second graph in the same graph how could we do that.. please see the picture

## width increase...

@Kitonum Dear sir thanks alot, now ut is working according to desire. the last thing i am facing that how to change the length of box that contains the legends...when i draw more the two-line e.g 5 line and i need to show 5 legends but the issue i am facing here is that the width of legends box increases and seem not good according to the graph box, i wish i want to adjust the length og legends box according to the graph.

## legend position...

@Kitonum i am trying to show legends inside the box ( on an empty place right corner or left corner)  but could not find any option. The available option is the only bottom, right, left, upward.please help me regarding this

plot([subs(a = 0.1, Q = 0.5, v), subs(a = 0.2, Q = 0.4, v)], x = 1 .. 10, style = pointline, colour = [black, red], symbol = [solidcircle, asterisk], symbolsize = 15, axes = boxed, numpoints = 20, legend = ["a = 0.1, Q = 0.5", "a = 0.2, Q = 0.4", location = righcorner])

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