@abbeykabir Ok, that's good. Now let's generalize that to the multivariate case, where x is an n-vector, and f is a vector-valued function on n-vectors (i.e., f: R^n -> R^n). In particluar, what corresponds to the derivative in the multivariable case?

@abbeykabir Ok, that's good. Now let's generalize that to the multivariate case, where x is an n-vector, and f is a vector-valued function on n-vectors (i.e., f: R^n -> R^n). In particluar, what corresponds to the derivative in the multivariable case?

laplace suffers from a severe case of "floating-point contagion"---the phenomenon that an expression with some floats acquires more floats after a transformation. You can see what's going on from lines 10-15 of showstat(inttrans[laplace]): If the original has any floats, then all rationals (including integers) in the result are converted to floats. The cure is as ThU says: Apply convert(..., rational) before calling laplace. Of course, as ThU said, laplace is not going to be of much help in solving this differential equation.

laplace suffers from a severe case of "floating-point contagion"---the phenomenon that an expression with some floats acquires more floats after a transformation. You can see what's going on from lines 10-15 of showstat(inttrans[laplace]): If the original has any floats, then all rationals (including integers) in the result are converted to floats. The cure is as ThU says: Apply convert(..., rational) before calling laplace. Of course, as ThU said, laplace is not going to be of much help in solving this differential equation.

@abbeykabir Let's start with what you do know. What do you know about Newton's method? Let's start with the single-variable case.

@abbeykabir Let's start with what you do know. What do you know about Newton's method? Let's start with the single-variable case.

I ran your code exactly as it is above in Maple 17.01 and I got that II, the symbolic imaginary part, is identically 0.

@abbeykabir Did he say that the answers are numerically wrong? Or did he just want you to use another method? There are likely to be multiple solutions to the system. Do you have any information about acceptable ranges for the y's? or some method to test whether a solution is feasible?

I'll write up an example using Newton's method.

@abbeykabir Did he say that the answers are numerically wrong? Or did he just want you to use another method? There are likely to be multiple solutions to the system. Do you have any information about acceptable ranges for the y's? or some method to test whether a solution is feasible?

I'll write up an example using Newton's method.

@puckie Yes, sorry, that statement is quite complicated. But note that it got significantly more complicated when you cut and pasted it. Learning that statement will take quite a bit of study. A place to start is ?LinearAlgebra,General,MVshortcut and ?$

@puckie Yes, sorry, that statement is quite complicated. But note that it got significantly more complicated when you cut and pasted it. Learning that statement will take quite a bit of study. A place to start is ?LinearAlgebra,General,MVshortcut and ?$

Can you show an example or post a worksheet?

@puckie The problem is that you have V:= [1,2,3,4,5,6], but you should have V:=[4,5,6,7,8,9,10].

@puckie The problem is that you have V:= [1,2,3,4,5,6], but you should have V:=[4,5,6,7,8,9,10].

@puckie On American keyboards, the underscore or underline is the shifted version of the minus sign. Note that the name y__1 contains two of these. The accent grave is the leftmost key is second row, to the left of number 1. The accents are not necessary in the name y__1 (but it shouldn't make any difference if you do use them). They are necessary for names that contain strange characters, such as `<|>` and the empty name ``, which has no characters.