Luna Laurent

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16 years, 329 days

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These are replies submitted by Luna Laurent

great! How did you do it?

What do those "

op(1,expr)*op(3,expr)"

etc. mean?


I have more expressions like this and I would like to apply your method to make the denominator as simple as possible...

Thanks a lot!

great! How did you do it?

What do those "

op(1,expr)*op(3,expr)"

etc. mean?


I have more expressions like this and I would like to apply your method to make the denominator as simple as possible...

Thanks a lot!

The numerator has factors g^(1), and g^(2/3),

 

the denominator has g^(2/3),

 

if I can get rid of the g^(2/3) on the denominator, then only g^(1/3) will remain on the numerator,

 

that's exactly what I want.

 

I just don't want any g on the denominator.

 

Thanks!

 

 

Okay,

 

this is the result after using the command "simplify",

 

but as you could see,

 

-(1/12)*(-g*vb-g+z*g-g^(2/3)*z+g^(2/3)*vb)*(g^(1/3)+1)^5/g^(2/3)

 

there is a common factor g^(2/3) on both the numerator and demoninator.

However I would like to remove such a common factor and therefore make the denominator as reduced as possible.

Any thoughts?

 

Thanks a lot!

 

 

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