baharm31

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These are questions asked by baharm31

Hi,

I am trying to find p and q from this simultaneous equation as a function of system parameters. I do not know the parameters and I need an expression. But Maple simply just gives p=0 and q=0 as an answer

Eq1:=61*q*L__1^2*C*e*eta/(16*omega__n^2)+5*q*L__1^2*C*e^3*eta^3/(8*omega__n^4)+3*C*p^3*gamma__1*(1/4)+3*q*C*p^2*R__n/(4*omega__n)+q*L__1^2*C*e^4*eta^4/(16*omega__n^5)+145*q*L__1^2*C/(64*omega__n)+3*q^3*C*R__n/(4*omega__n)+3*p*C*q^2*gamma__1*(1/4)+q*R*C/(4*omega__n)+19*q*L__1^2*C*e^2*eta^2/(8*omega__n^3):
Eq2:=-3*C*p^3*R__n/(4*omega__n)-3*p*C*q^2*R__n/(4*omega__n)-p*L__1^2*C*e^4*eta^4/(16*omega__n^5)-5*p*L__1^2*C*e^3*eta^3/(8*omega__n^4)-19*p*L__1^2*C*e^2*eta^2/(8*omega__n^3)-61*p*L__1^2*C*e*eta/(16*omega__n^2)-145*p*L__1^2*C/(64*omega__n)-p*R*C/(4*omega__n)+3*q*C*p^2*gamma__1*(1/4)+3*q^3*C*gamma__1*(1/4):
sys := { Eq1 , Eq2 };solve( sys, {p,q} );

Is there any way to help Maple to try other conditions, I know the only solution should not be just p=0 and q=0.

Thanks,

Baharm31

 

 

Hi,

I have an expression and want to find its derivative respect to T[1] but not T[2], for example: 

u[1](T[1], T[2], T[3]):=exp(T[1]*I)

If I find the 

diff(u[1](T[1], T[2], T[3]), T[1], T[2])

I would like to get something like this:

D__1*diff(u[1](T[1], T[2], T[3]), T[1])

instead of the derivative respect to T[2], which makes the result to be zero.

I need an expression that I can do other things with it.

You might say why do you just remove the diff of T[2], well I want to automate my code and this is part of the expression so I cannot write something else.

Regards,

Bahar

Hi,

I want to find the real and Imaginary part of this equation, without losing the exponential forms. 

(I*(1/2))*(I*R*C*C1*omega__n-L__1*C*exp(I*eta*T[2])*e^2*eta^2*C2-5*L__1*C*exp(I*eta*T[2])*e*eta*omega__n*C2+(3*I)*R__n*C*C1^2*C2*omega__n-3*gamma__1*C*C1^2*omega__n^2*C2-13*L__1*C*exp(I*eta*T[2])*omega__n^2*C2*(1/2))/omega__n

If I use 

evalc(Im(D1C1))

then the exp changes to sin or cos forms. How can I prevent it?

Regards,

Bahar

Hi,

Is there any way to define a specific part of an equation to be integrated in respect to time T[1]?

In my attached example I try to integrate the right hand side after isolating for C1D__1 (removing the effect of C1D__1) and maybe isolation is not the right thing to do. Any idea?


coeff1 := 5*L__1*C*exp(I*T[1]*e*eta)*e*eta*C2/omega__n-(2*I)*D__1*C1/omega__n+L__1*C*exp(I*T[1]*e*eta)*e^2*eta^2*C2/omega__n^2-(3*I)*R__n*C*C1^2*C2/omega__n+3*gamma__1*C*C1^2*C2-I*R*C*C1/omega__n+13*L__1*C*exp(I*T[1]*e*eta)*C2*(1/2):
isolate(coeff1, D__1)*C1:

integrate the right hand side of the equation with T[1]

Thanks,

Bahar

 

 

Hi,

I have an expression like x:= C*exp(I*T[1]*e*eta) and want to define e*T[1] as T[2]. How can I do this with coding?

Regards,

Bahar

 

 

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