## 669 Reputation

19 years, 279 days

## an explanation...

So the number 1 means that the sequence 010 appeared in pi? In the first 10000 digits, you expect this about 100 times. The same for 2 through 9. In fact, then, 1 through 9 are in the upper left (log 9 = 2.2), each with about 100 hits. Next, 11 through 99 (log 99 = 5.6), each with bout 10 hits. Then we expect 111 through 999, each with about 1 hit (log 999 = 6.9) and above that only every tenth number up to 9999 gets a hit. --- G A Edgar

## not Benford...

in Benford's Law, numbers are not allowed to begin with 0... --- G A Edgar

Don't these two contradict each other? u3d became a popular format and only CAD and Framemaker seem to have u3d export --- G A Edgar

## Mac OS X...

This should already work in Maple on Mac. In all mac applications, when you "print", you get the option of printing to a PDF file instead of paper. --- G A Edgar

## Well......

Maple may say that 0^0 is 1, but it doesn't say that for 0.0^0.0; The definition for a^b where the exponent b is complex is a^b = exp(b*log(a)), so it should be undefined for a=0. > 0^0; 1 > 0.0^0.0; Float(undefined) > subs(x=0,sum(x^k,k=0..4)) = sum(subs(x=0,x^k),k=0..4); 1 = 0 > 0^(1+I); 0 > 0^I; Error, numeric exception: division by zero > 0^(-1+I); infinity + infinity I --- G A Edgar

## I think that is not what he wants...

I think he wants to input an equation like eq1 := A*B = C; or maybe . or &* or some other symbol for the multiply. Here A, B, C are just letters. We know they are matrices, but Maple has not been told a size or anything like that. Then he wants to enter solve(eq1,B); and get the result inverse(A)*C or maybe something other than "inverse" We want to "solve" for a non-commutative multiplication. There is a way to define your own operations, and give them properties. But can you give them an "inverse" and then solve as above? --- G A Edgar

## I think that is not what he wants...

I think he wants to input an equation like eq1 := A*B = C; or maybe . or &* or some other symbol for the multiply. Here A, B, C are just letters. We know they are matrices, but Maple has not been told a size or anything like that. Then he wants to enter solve(eq1,B); and get the result inverse(A)*C or maybe something other than "inverse" We want to "solve" for a non-commutative multiplication. There is a way to define your own operations, and give them properties. But can you give them an "inverse" and then solve as above? --- G A Edgar

## what?...

so ... I I would have < a > defined and also defined .. and if the value of t would change I would be able to find the answers ... what happens if In my equation I have a polynomial ..... of I juste have the A pressent

I am sorry. i do not understand your English. --- G A Edgar

## what?...

so ... I I would have < a > defined and also defined .. and if the value of t would change I would be able to find the answers ... what happens if In my equation I have a polynomial ..... of I juste have the A pressent

I am sorry. i do not understand your English. --- G A Edgar

## still rsolve...

For Maple, write it with ( ) rather than _ , though. > `rsolve({y(t)-a*y(t-1)=A*p^t,y(0)=y0},y(t));` y0*a^t+A/(-p+a)*p*a^t-A/(-p+a)*p*p^t --- G A Edgar

## still rsolve...

For Maple, write it with ( ) rather than _ , though. > `rsolve({y(t)-a*y(t-1)=A*p^t,y(0)=y0},y(t));` y0*a^t+A/(-p+a)*p*a^t-A/(-p+a)*p*p^t --- G A Edgar

## Lagrange multiplier maximum...

f=1000*x+7500*y under constraint: g=10000000-(20000*x^0.8)*y^1.2 I guess your problem is trying to find a nonexistent solution. As x -> 0, y -> infinity and f -> infinity. There is no maximum. There is a minimum value of 1.46*10^5 at around x=58,y=12. Is that what you wanted to find? --- G A Edgar

## reminds me...

[[being of an engineering background, most of your list do not resonate with me ]] I remember once talking with an astronomer, who was surprised to find that I considered Gauss to be a mathematician rather than an astronomer. --- G A Edgar

## reminds me...

[[being of an engineering background, most of your list do not resonate with me ]] I remember once talking with an astronomer, who was surprised to find that I considered Gauss to be a mathematician rather than an astronomer. --- G A Edgar

## --- G A Edgar>...

Here is my attempt. First with Maple input, then with 2D input...

> interface(version);

> (a^t)^2;

> simplify(%);

>

> simplify(%);

>

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