What's this "AFAIC" ?
As Far As I See ?
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G A Edgar

What's this "AFAIC" ?
As Far As I See ?
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G A Edgar

When you say numpoints=100, doesn't that cause evaluation at 100 equally-spaced points (which, in this case, are all rational)???
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G A Edgar

It seems Maple only has the "Fortran" function, which translates from Maple to Fortran.
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G A Edgar

What is the one name in the 362 not in the 361?
What are some examples in S2 but not S1?
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G A Edgar

That thing with the zeta functions from identify: In fact it only agrees to 8 places, so don't believe it.
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G A Edgar

You think it is an algebraic trick? Look at this:
A1 := hypergeom([-1/2, 3/8, 169/88], [81/88, 19/8], z);
A1 := hypergeom([-1/2, 3/8, 169/88], [81/88, 19/8], z)
A2 := subs(z=-1/6,A1);
A2 := hypergeom([-1/2, 3/8, 169/88], [81/88, 19/8], -1/6)
identify(evalf(A2,50));
(77/486)*42^(1/2)
A3 := subs(z=1,A1);
A3 := hypergeom([-1/2, 3/8, 169/88], [81/88, 19/8], 1)
evalf(A3,50);
.78544208367808523114057318033434606661653742464155
identify(%);
10*3^(6/7)*ln(2)^7/Zeta(3)^5
Now, if you prove A3 is algebraic, you will be famous!

The guesses on where it comes from are both right.
I started with the problem in
www.mapleprimes.com/forum/thomascalculus5615exercisegetshypergeom
which is a sum of two terms, both involving 2F1's, then converted to Int, combined them, and evaluated. Voila, a new problem, now involving a 3F2.
My guess is that although
hypergeom([-1/2, 3/8, 169/88], [81/88, 19/8], -1/6)
has a nice closed form,
hypergeom([-1/2, 3/8, 169/88], [81/88, 19/8], z)
doesn't. But that's just a guess.
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G A Edgar

As a mathematician, I never thought that
Sin[x]
was right, instead of
sin(x)
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G A Edgar

My errors tend to look like this...
for i from 1 to 5 do i; od;
1
2
3
4
5
sum(2,i=1..5);
Error, (in sum) summation variable previously assigned, second argument evaluates to 6 = 1 .. 5
sum(2,'i'=1..5);
10
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G A Edgar

When you reply, see the "Input Format" option below. Click it to see the explanations.
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G A Edgar

And now someone else has removed that example completely?
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G A Edgar

How about solving for the inverse function? solve for k in terms of t...
solve(eq3,k) yields an answer, involving not only exp, sin, cos, but also LambertW.
k = t*sin(t)/(LambertW(-t/(exp(cos(t)*t/sin(t))*sin(t)))*sin(t)+cos(t)*t)
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G A Edgar

How about solving for the inverse function? solve for k in terms of t...
solve(eq3,k) yields an answer, involving not only exp, sin, cos, but also LambertW.
k = t*sin(t)/(LambertW(-t/(exp(cos(t)*t/sin(t))*sin(t)))*sin(t)+cos(t)*t)
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G A Edgar

Maple 12 has the option: Default magnification 125%
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G A Edgar