jerzy

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12 years, 122 days

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These are questions asked by jerzy

Hello,

How can I get the powers of "y" for all terms in eq1:

eq1:=A*(k+1)*y^n+(k+2)*y^(n+1)+12*y^n+k*y^6 +... other terms

where A,k, = consts, n::posint

,for example, as a list  [n,n+1,n,6,....]

Thanks in advance - jerzy 

Hello,

 

how to simplify lhs(eq) to get rhs(eq)?

eq:=y*(sum(a[n]*y^(n-2)*n*(n-1), n = 0 .. infinity)) = (sum(a[n]*y^(n-1)*n*(n-1), n = 0 .. infinity));

is(eq);    

Regards

Jerzy

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