## 76 Reputation

17 years, 291 days

## Good Morning Doug: This must...

Good Morning Doug: This must be the 5th time you responded to my questions. Your responses were not only very useful and instructive particularly this latest one, but enhanced and expanded my skill in the use of the maple system. As always, thank you very much. Pat

## Good Morning Doug: This must...

Good Morning Doug: This must be the 5th time you responded to my questions. Your responses were not only very useful and instructive particularly this latest one, but enhanced and expanded my skill in the use of the maple system. As always, thank you very much. Pat

## Hi Robert Israel: Thank you...

Hi Robert Israel: Thank you for your comment. I knew someone in the community will clarify my mistake. I tried your statement. It is much simplier and yet does what I wanted to do. Thank you for your suggestion. If you can take another question, I wanted to process b2 so that it becomes b2=sqrt(14.2^2+16.2^2-2*14.2*16.2*cos(115)) without actually Maple performing the arithmetic operations inside the square root symbol. I am trying to demonstrate to my students the actual substitution of the values into the formula. Thank you in advance. Pat

## Hi Robert Israel: Thank you...

Hi Robert Israel: Thank you for your comment. I knew someone in the community will clarify my mistake. I tried your statement. It is much simplier and yet does what I wanted to do. Thank you for your suggestion. If you can take another question, I wanted to process b2 so that it becomes b2=sqrt(14.2^2+16.2^2-2*14.2*16.2*cos(115)) without actually Maple performing the arithmetic operations inside the square root symbol. I am trying to demonstrate to my students the actual substitution of the values into the formula. Thank you in advance. Pat

## Animation...

Thanks for responding. When I tried your solution, f1 did not remain in the graph when f2 was graphed. Although this is not the solution I was looking for, you introduced me to "with(geometry)" which I have not used before. Thank for your ideas. Pat

## Animation...

Thanks for responding. When I tried your solution, f1 did not remain in the graph when f2 was graphed. Although this is not the solution I was looking for, you introduced me to "with(geometry)" which I have not used before. Thank for your ideas. Pat

## Thank you for responding to...

Thank you for responding to my call. I am using Maple 10.6. Were you able to figure to avoid this problem. I have lost a lot of work time as a result of this problem.

## Thank you for responding to...

Thank you for responding to my call. I am using Maple 10.6. Were you able to figure to avoid this problem. I have lost a lot of work time as a result of this problem.

## Labeling plotted points...

Thank you once more for responding to my question. I tried your suggestion in maple and it works. p1:=plot([[0,0],[15,0],[24.50,9.69],[0,0]],filled=true); t1:=textplot([0,0,"Angle A"],align=BELOW); t2:=textplot([15,0,"Angle C"],align=BELOW); t3:=textplot([24.50,9.69,"Angle B"],align=ABOVE); display({p1,t1,t2,t3}); However, I am having difficulty translating the maple code into maplet. So far my maplet looks as follows and I like to label [0,0] as Angle A,[15,0] as Angle C and [24.50,9.69] as Angle B: BoxRow('border'='true','caption'="Triangle",halign=none, 'font'=Font("Arial",14), Plotter['PL1'](plot([[0,0],[15,0],[24.50,9.69],[0,0]], filled=true), width=275,height=150) ) Or is this even possible in maplet? Thank you for what ever assistance you may provide.

## Substitution without evaluation...

Thanks. It may not be elegant but a smart approach. It may work for my needs. Thank you again.,

## How to plot the area bounded by...

Exactly what I meant. Thank you.

## Thank you for responding....

Thank you for responding. Unfortunately I may have not expressed my question clearly. I wanted to create a graph highlighting the area bounded by [f(x),x=a, and x=b] over the domain from x=c to x=d where [a,b] is in [c,d]. In other words the graph of [f(x),x=a, and x=b] is a subset of the area from x=c and x=d. Again thank you for your time.
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