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Hi all, thanks for all the help so far. I have this nonlinear differential equation with boundary conditions. I have tried quite few ways but nothing has worked so far. x := diff(y(r), r, r)+2*(diff(y(r), r))/r+1.5*(16*4300)*Pi^2*10^6*sqrt(Pi/(2*0.128e-2^3))*polylog(3/2, exp(0.128e-2*(1194.3-y(r)))) = 0; boundary conditions: bc:= D(y)(0) = 0, y(infinity) = 0 Thanks in advance MS
Hi there, I don't find the right command that let's me plot parametrized curves in 3D. So lets say i wanna plot a srew fether, that is parametrized as follows: g: [0,10π] -> R³ : t -> g(t) = [cos(t),sin(t),] How do i do this? -.^

Hi,

I would like to get to the numeric values that are calculated by creating a plot using implicitplot.

Any help or pointers are greatly appreciated.

M.

Windows Vista Home Premium+Maple 13+Maple toolbox for MATLAB 13+Matlab R2009a

Error Message: MATLAB not found!

I am confused with this question. I have parabola1 which is 3*x^2-22x+7, and parabola2 which is -5/9*x^2+58/9*x-161/9. the area of par1 is −148.1481481, the area of par2 is −1.280000000.

How can I Calculate the area A3 which is defined by the intersections
of Par1 and Par2.
and Plot Par1 and Par2 with the area A3 “highlighted

thanks

Hi guys, I am struggling with these three equations. The first is a nonlinear equation which can be solved numerically with the boundary conditions y(infinity)=0 and y'(0)=0. a1 := diff(y(r), r, r) = -2*(diff(y(r), r))/r-1.3*10^12*polylog(3/2, exp(b(u-y(r)))) Now y(r) depends parametrically on u and b which can be determined using these equations: a2 := -1.5*10^8*(int((3*polylog(5/2, exp(b(u-y(r))))/b^(5/2)+y(r)*polylog(3/2, exp(b(u-y(r))))/b^(3/2))*r^2, r = 0 .. 10)) = -129000 a3 := 3*10^8*(int(r^2*polylog(3/2, exp(b(u-y(r)))), r = 0 .. 10))/b^(3/2) = 1
I am having a problem in indexing a given matrix to be used in sigma. How can I make this work? x-y coordinate method > xy := Matrix(5, 2, {(1, 1) = 10, (1, 2) = 10, (2, 1) = -14, (2, 2) = -2, (3, 1) = -10, (3, 2) = -10, (4, 1) = 4, (4, 2) = -24, (5, 1) = 10, (5, 2) = 10}); > n := LinearAlgebra[RowDimension](xy); = print(`output redirected...`); # input placeholder 5 > > x := LinearAlgebra[Column](xy, 1); = print(`output redirected...`); # input placeholder Vector[column](%id = 194172504)

I am attempting to solve the following problem with maple:

 

3 ∙ x ≡ 1 (mod(2))

Yet when entering this into maple I get the following error:

Error, invalid input: modp expects 2 arguments, but received 1

So how would one enter this problem into maple?  What other argument would need to be entered or can maple even solve this?

 

restart:

stats[random,binomiald[400,1/2]](4);

                            88, 88, 88, 88

 

The first four values generated by the binomial random number generator

with n=400 and p=1/2 are all equal to 88? I must be doing something wrong.

Any ideas? (I am using Maple 8)

 

Byron Schmuland


 

I know this sort of simplify question has been asked many times, but I still don't seem to have 'got it'.  In a nutshell, there's a conservative real 2-D vector field (cartesian X,Y coordinates) with an extra non-positive parameter Z, and Maple 12 is able to compute the scalar potential.  But it presents it in a long (6 lines), perversely complicated form, involving the imaginary sqrt(-Y^2).  I tried to show it here using the Maple leaf Tag and pasting the expressions there, but all I got was indecipherable ascii.  The vector field X and Y components are

Dear all,

    I want to find a relation between tow sets of discrete points. So I must plot a curve with these dicrete point pairs. But  the two sets points don't have a explict relation (in fact, the relation just is that I want to find) How  to treat the discrete point pairs with maple? Thank you very much!

Best regards!

 

I was wondering if there was a way to have two background plots on an animation?  I would like 2 seperate parts of the animation to remain constant but I can't figure out how to do that without connecting the seperate parts.

Thanks.

 

hi, I m pretty new with maple,  could someone tell me how to calculat the area of parabola and x-axis,the equation of parabola is 3x^2-22x+7,

Hey so I've been given a set of data, I was told to make a scatter plot which i did now I have to:

 

Use the regression feature of Maple to find a linear model of the data.

 

I don't know how to do this. What I have right now is:

> data := [[2005, 2.85], [2006, 5.70], [2007, 10.0], [2008, 14.8], [2011, 25.0]];
   [[2005, 2.85], [2006, 5.70], [2007, 10.0], [2008, 14.8], [2011, 25.0]]
> with(plots);
> pointplot(data);

 

What's the next step?

 

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