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Issue in Determining Optimal KKT Multipl...

Andiguys 85 Maple 2019
optimization duplicate-question
October 19 2025
0 0

I am attempting to solve an optimization problem using the Karush–Kuhn–Tucker (KKT) conditions, where the objective function is to be maximized subject to a constraint that may or may not be binding. However, when solving the system, the KKT multiplier (μ1​) consistently evaluates to zero, even when the constraint appears to be active. I am unable to determine the optimal value of μ1​ and seek guidance on how to obtain the optimal values of Pn, Pr, and w, as well as the correct condition for μ1​.

> 

``
> 

restart
> 

with(Optimization); with(plots); with(LinearAlgebra)
> 

_local(Pi)

Pi

 (1)
> 

``
> 

`π_m` := proc (Pn, Pr, w) options operator, arrow; (Pn-Cn)*(1-(Pn-Pr)/(1-delta))+(Pr-w-Crm)*alpha*(1/2+(1/2)*((Cr*Pn*i2-Cr*Pn*tau-Cr*Pr*i2+Cr*Pr*tau+Cr*delta*i2-Cr*delta*tau+2*delta*i2*tau-2*delta*tau^2+2*w*tau*delta-Cr*i2+Cr*tau-2*i2*tau+2*tau^2-2*w*tau)/(Cr*Pn-Cr*Pr+Cr*delta+4*tau*delta-Cr-4*tau)-i2)/tau)*(1-(Pn-Pr)/(1-delta))-Ce*rho0*(1-(Pn-Pr)/(1-delta)) end proc

proc (Pn, Pr, w) options operator, arrow; (Pn-Cn)*(1-(Pn-Pr)/(1-delta))+(Pr-w-Crm)*alpha*(1/2+(1/2)*((Cr*Pn*i2-Cr*Pn*tau-Cr*Pr*i2+Cr*Pr*tau+Cr*delta*i2-Cr*delta*tau+2*delta*i2*tau-2*delta*tau^2+2*w*tau*delta-Cr*i2+Cr*tau-2*i2*tau+2*tau^2-2*w*tau)/(Cr*Pn-Cr*Pr+Cr*delta+4*tau*delta-Cr-4*tau)-i2)/tau)*(1-(Pn-Pr)/(1-delta))-Ce*rho0*(1-(Pn-Pr)/(1-delta)) end proc

 (2)
> 

``
> 

``
> 

NULL
> 

C1 := (((Cr+4*tau)*delta-4*tau+(Pn-Pr-1)*Cr)*rho0+(delta-1)*(i2-tau))/(delta-1) <= w

(((Cr+4*tau)*delta-4*tau+(Pn-Pr-1)*Cr)*rho0+(delta-1)*(i2-tau))/(delta-1) <= w

 (3)
> 

NULL
> 

# No equality constraints
 
      f[1] := (Pn,Pr,w) -> (((Cr + 4*tau)*delta - 4*tau + (Pn - Pr - 1)*Cr)*rho0 + (delta - 1)*(i2 - tau))/(delta - 1)-w:

 
> 

# Lagrangian (we want to maximize `&pi;_m` so to minimize -`&pi;_m`

L := -`&pi;_m`(Pn,Pr,w) + add(f[i](Pn,Pr,w)*mu[i], i=1):
> 

dLdPn := collect(diff(L, Pn), [Pn]):
dLdPr := collect(diff(L, w), [Pr]):
dLdw := collect(diff(L, w), [w]):
> 

KKT_conditions := [
                    seq(mu[i] >= 0, i=1),         # Dual feasibility conditions
                    dLdPn = 0,  
dLdPr = 0,
dLdw = 0,                     # Stationarity condition
                    seq(``(f[i](Pn,Pr,w)) <= 0, i=1),  # Primal feasibility conditions
                    add(mu[i]*f[i](Pn,Pr,w) = 0, i=1)  # Complementary slackness
                  ]:

 print~(KKT_conditions):

0 <= mu[1]

  

-1+(Pn-Pr)/(1-delta)+(Pn-Cn)/(1-delta)-(1/2)*(Pr-w-Crm)*alpha*((Cr*i2-Cr*tau)/(Cr*Pn-Cr*Pr+Cr*delta+4*delta*tau-Cr-4*tau)-(Cr*Pn*i2-Cr*Pn*tau-Cr*Pr*i2+Cr*Pr*tau+Cr*delta*i2-Cr*delta*tau+2*delta*i2*tau-2*delta*tau^2+2*delta*tau*w-Cr*i2+Cr*tau-2*i2*tau+2*tau^2-2*tau*w)*Cr/(Cr*Pn-Cr*Pr+Cr*delta+4*delta*tau-Cr-4*tau)^2)*(1-(Pn-Pr)/(1-delta))/tau+(Pr-w-Crm)*alpha*(1/2+(1/2)*((Cr*Pn*i2-Cr*Pn*tau-Cr*Pr*i2+Cr*Pr*tau+Cr*delta*i2-Cr*delta*tau+2*delta*i2*tau-2*delta*tau^2+2*delta*tau*w-Cr*i2+Cr*tau-2*i2*tau+2*tau^2-2*tau*w)/(Cr*Pn-Cr*Pr+Cr*delta+4*delta*tau-Cr-4*tau)-i2)/tau)/(1-delta)-Ce*rho0/(1-delta)+Cr*rho0*mu[1]/(delta-1) = 0

  

alpha*(1/2+(1/2)*((Cr*Pn*i2-Cr*Pn*tau-Cr*Pr*i2+Cr*Pr*tau+Cr*delta*i2-Cr*delta*tau+2*delta*i2*tau-2*delta*tau^2+2*delta*tau*w-Cr*i2+Cr*tau-2*i2*tau+2*tau^2-2*tau*w)/(Cr*Pn-Cr*Pr+Cr*delta+4*delta*tau-Cr-4*tau)-i2)/tau)*(1-(Pn-Pr)/(1-delta))-(1/2)*(Pr-w-Crm)*alpha*(2*delta*tau-2*tau)*(1-(Pn-Pr)/(1-delta))/((Cr*Pn-Cr*Pr+Cr*delta+4*delta*tau-Cr-4*tau)*tau)-mu[1] = 0

  

alpha*(2*delta*tau-2*tau)*(1-(Pn-Pr)/(1-delta))*w/((Cr*Pn-Cr*Pr+Cr*delta+4*delta*tau-Cr-4*tau)*tau)+alpha*(1/2+(1/2)*((Cr*Pn*i2-Cr*Pn*tau-Cr*Pr*i2+Cr*Pr*tau+Cr*delta*i2-Cr*delta*tau+2*delta*i2*tau-2*delta*tau^2-Cr*i2+Cr*tau-2*i2*tau+2*tau^2)/(Cr*Pn-Cr*Pr+Cr*delta+4*delta*tau-Cr-4*tau)-i2)/tau)*(1-(Pn-Pr)/(1-delta))-(1/2)*(Pr-Crm)*alpha*(2*delta*tau-2*tau)*(1-(Pn-Pr)/(1-delta))/((Cr*Pn-Cr*Pr+Cr*delta+4*delta*tau-Cr-4*tau)*tau)-mu[1] = 0

  

``((((Cr+4*tau)*delta-4*tau+(Pn-Pr-1)*Cr)*rho0+(delta-1)*(i2-tau))/(delta-1)-w) <= 0

  

((((Cr+4*tau)*delta-4*tau+(Pn-Pr-1)*Cr)*rho0+(delta-1)*(i2-tau))/(delta-1)-w)*mu[1] = 0

 (4)

 

> 

NULL


Download Solve_mu1.mw

μ₁ and μ₂ conditions in constrained opti...

Andiguys 85 Maple 2019
optimization lagrange-multipliers duplicate-question
September 29 2025
1 10

I am optimizing an objective function subject to two constraints. I have obtained the solution, but I am unsure how to determine the conditions for the Lagrange multipliers μ1​ and μ2​. For example, using the KKT conditions, if μ1>0 then the solution is X, and if μ2>0 then the solution is Y. Could you guide me on how to find μ1 and μ2 along with their corresponding conditions?

> 

restart
> 

with(Optimization); with(plots); with(LinearAlgebra)
> 

_local(Pi)

Pi

 (1)
 
> 

`&pi;_m` := proc (i1) options operator, arrow; (w-i1)*(1/2+(1/2)*(i1-i2)/tau)*(1-(Pn-Pr)/(1-delta))-C0-(1/2)*Cr*(1/2+(1/2)*(i1-i2)/tau)^2*(1-(Pn-Pr)/(1-delta))^2+Ce*rho0*(1-(Pn-Pr)/(1-delta)) end proc
> 

C1 := (2*rho0-1)*tau+i2 <= i1

(2*rho0-1)*tau+i2 <= i1

 (2)
> 

C2 := i1 <= tau+i2

i1 <= tau+i2

 (3)
> 

NULL
> 

NULL
> 

``
> 

NULL
> 

# No equality constraints
#
# Inequality constraints must be of the form f[i](i1) <= 0
#
# Thus
#
# (1) For C1
#     so
      f[1] := (i1) -> (2*rho0 - 1)*tau + i2-i1:
      
#
# (2) C2
#     so
      f[2] := (i1) -> i1-(tau + i2):
      
#
> 

# Lagrangian (we want to maximize `&pi;_m` so to minimize -`&pi;_m`

L := -`&pi;_m`(i1) + add(f[i](i1)*mu[i], i=1..2):
> 

dLdi1 := collect(diff(L, i1), [i1]):
> 

KKT_conditions := [
                    seq(mu[i] >= 0, i=1..2),         # Dual feasibility conditions
                    dLdi1 = 0,                       # Stationarity condition
                    seq(``(f[i](i1)) <= 0, i=1..2),  # Primal feasibility conditions
                    add(mu[i]*f[i](i1) = 0, i=1..2)  # Complementary slackness
                  ]:

print~(KKT_conditions);

0 <= mu[1]

  

0 <= mu[2]

  

((1-(Pn-Pr)/(1-delta))/tau+(1/4)*Cr*(1-(Pn-Pr)/(1-delta))^2/tau^2)*i1+(1/2-(1/2)*i2/tau)*(1-(Pn-Pr)/(1-delta))-(1/2)*w*(1-(Pn-Pr)/(1-delta))/tau+(1/2)*Cr*(1/2-(1/2)*i2/tau)*(1-(Pn-Pr)/(1-delta))^2/tau-mu[1]+mu[2] = 0

  

``((2*rho0-1)*tau+i2-i1) <= 0

  

``(i1-tau-i2) <= 0

  

((2*rho0-1)*tau+i2-i1)*mu[1]+(i1-tau-i2)*mu[2] = 0

  

[]

 (4)


Analysis of dLdp1

> 

with(LargeExpressions):

DLDi1 := collect(dLdi1, i1, Veil[K]);

(1/4)*K[1]*i1-(1/4)*K[2]

 (5)
> 

# Thus dLdi1 = 0 verifies

isolate((5), i1)
 

i1 = K[2]/K[1]

 (6)
> 

# Where K1 and K2 are

i := 'i':
KS := [ seq(K[i] = Unveil[K](K[i]), i=1..LastUsed[K] ) ];

[K[1] = (-1+delta+Pn-Pr)*(Cr*Pn-Cr*Pr+Cr*delta+4*delta*tau-Cr-4*tau)/(tau^2*(-1+delta)^2), K[2] = (4*delta^2*tau^2*mu[1]-4*delta^2*tau^2*mu[2]+Cr*Pn^2*i2-Cr*Pn^2*tau-2*Cr*Pn*Pr*i2+2*Cr*Pn*Pr*tau+2*Cr*Pn*delta*i2-2*Cr*Pn*delta*tau+Cr*Pr^2*i2-Cr*Pr^2*tau-2*Cr*Pr*delta*i2+2*Cr*Pr*delta*tau+Cr*delta^2*i2-Cr*delta^2*tau+2*Pn*delta*i2*tau-2*Pn*delta*tau^2+2*Pn*delta*tau*w-2*Pr*delta*i2*tau+2*Pr*delta*tau^2-2*Pr*delta*tau*w+2*delta^2*i2*tau-2*delta^2*tau^2+2*delta^2*tau*w-8*delta*tau^2*mu[1]+8*delta*tau^2*mu[2]-2*Cr*Pn*i2+2*Cr*Pn*tau+2*Cr*Pr*i2-2*Cr*Pr*tau-2*Cr*delta*i2+2*Cr*delta*tau-2*Pn*i2*tau+2*Pn*tau^2-2*Pn*tau*w+2*Pr*i2*tau-2*Pr*tau^2+2*Pr*tau*w-4*delta*i2*tau+4*delta*tau^2-4*delta*tau*w+4*tau^2*mu[1]-4*tau^2*mu[2]+Cr*i2-Cr*tau+2*i2*tau-2*tau^2+2*tau*w)/(tau^2*(-1+delta)^2)]

 (7)


Analysis of the two constraints

> 

beta

beta

 (8)
> 

Cs := { seq(beta[i] = subs(i1=0, f[i](i1)), i=1..2) };

{beta[1] = (2*rho0-1)*tau+i2, beta[2] = -tau-i2}

 (9)
> 

 

> 

# two constraints problem

Cmin_value := min(rhs~(Cs));  # the "true" constraints
Cmax_value := max(rhs~(Cs)):

Cmin_name  := min(lhs~(Cs));  # the "abstract" constraints
Cmax_name  := max(lhs~(Cs)):

Cmin_name  := LowerBound;  # and an even more abstract form
Cmax_name  := UpperBound:

Complementary_Slackness := mu[1]*(Cmin_name-i1) , mu[2]*(i1-Cmax_name);

L2     := -`&pi;_m`(i1) + add(Complementary_Slackness):
dL2di1 := diff(L2, i1):
dL2di1 := map(simplify, %, size);
 

min(-tau-i2, (2*rho0-1)*tau+i2)

  

min(beta[1], beta[2])

  

LowerBound

  

mu[1]*(LowerBound-i1), mu[2]*(i1-UpperBound)

  

(1/2)*(tau+i1-i2)*(-1+delta+Pn-Pr)/(tau*(-1+delta))+(1/2)*(-w+i1)*(-1+delta+Pn-Pr)/(tau*(-1+delta))+(1/4)*Cr*(tau+i1-i2)*(-1+delta+Pn-Pr)^2/(tau^2*(-1+delta)^2)-mu[1]+mu[2]

 (10)
> 

type(dL2di1, linear([i1, seq(mu[i], i=1..2)]));

SC_CS_sols := solve(
  {
    dL2di1 = 0,
    op([Complementary_Slackness] =~ 0)
  }
  ,
  {i1, seq(mu[i], i=1..2)}
):

true

  

Main: Entering solver with 3 equations in 3 variables
Main: attempting to solve as a linear system
Main: attempting to solve as a polynomial system
Main: Polynomial solver successful. Exiting solver returning 1 solution

  
> 

# How many solutions did we get?

numelems([SC_CS_sols]);

# And those solutions are charecterized by

map(s -> if eval(lambda[1], s) = 0 then
           if eval(lambda[2], s) = 0 then
             "i1 belongs to interval (LowerBound, UpperBound)"
           else
             "i1 is equal to the UpperBound"
           end if
         else
           "i1 is equal to the LowerBound"
         end if
         , [SC_CS_sols]);

# So we get as expected the three possible situations.

3

  

["i1 is equal to the LowerBound", "i1 is equal to the LowerBound", "i1 is equal to the LowerBound"]

 (11)
> 

Cmin_value

min(-tau-i2, (2*rho0-1)*tau+i2)

 (12)
 

 

Download I_1_Optimum_condition.mw

Taking so much time to solve?...

Andiguys 85 Maple 2019
solve parametric duplicate-question
September 26 2025
2 9

Easy way to solve 3 equation simultaneously?:

> 

restart
> 

with(Optimization); with(plots); with(LinearAlgebra)
 
> 

K2 := -(Pn-Pr)/(1-delta)+(-beta*((-2*delta+2)*tau^2+((-Pn+Pr-delta+1)*Cr+(-2+2*delta)*(w+i2))*tau+Cr*i2*(-1+delta+Pn-Pr))*upsilon/((4*delta-4)*tau+Cr*(-1+delta+Pn-Pr))+Pr)/delta+(Pr-w-Cr)*beta*(-2+2*delta)*tau*upsilon/(((4*delta-4)*tau+Cr*(-1+delta+Pn-Pr))*delta) = 0

 

 (1)
> 

K3 := 1-(Pn-Pr)/(1-delta)-(Pn-Cn)/(1-delta)+(Pr-w-Cr)*(1/(1-delta)-(-beta*(Cr*i2-Cr*tau)*upsilon/((4*delta-4)*tau+Cr*(-1+delta+Pn-Pr))+beta*((-2*delta+2)*tau^2+((-Pn+Pr-delta+1)*Cr+(-2+2*delta)*(w+i2))*tau+Cr*i2*(-1+delta+Pn-Pr))*upsilon*Cr/((4*delta-4)*tau+Cr*(-1+delta+Pn-Pr))^2)/delta)+Ce*rho0/(1-delta) = 0

 

 (2)
> 

K4 := (Pn-Cn)/(1-delta)+(Pn-Pr)/(1-delta)-(-beta*((-2*delta+2)*tau^2+((-Pn+Pr-delta+1)*Cr+(-2+2*delta)*(w+i2))*tau+Cr*i2*(-1+delta+Pn-Pr))*upsilon/((4*delta-4)*tau+Cr*(-1+delta+Pn-Pr))+Pr)/delta+(Pr-w-Cr)*(-1/(1-delta)-(-beta*(-Cr*i2+Cr*tau)*upsilon/((4*delta-4)*tau+Cr*(-1+delta+Pn-Pr))-beta*((-2*delta+2)*tau^2+((-Pn+Pr-delta+1)*Cr+(-2+2*delta)*(w+i2))*tau+Cr*i2*(-1+delta+Pn-Pr))*upsilon*Cr/((4*delta-4)*tau+Cr*(-1+delta+Pn-Pr))^2+1)/delta)-Ce*rho0/(1-delta) = 0

 

 (3)
> 

sol := solve({K2, K3, K4}, {Pn, Pr, w})

Download Q_solve.mw

Simplifying the expression?...

Andiguys 85 Maple 2019
solve simplify substitution
September 22 2025
2 1

While solving for i1 encounter too many terms. How can I simplify it so that only " Pn,Pr and w" remain, with all other variables grouped into constants, so that the equation for the optimal i1​ becomes small and manageable?

> 

restart
> 

kernelopts(version)

`Maple 2019.1, X86 64 WINDOWS, May 21 2019, Build ID 1399874`

 (1)
> 

Pi1 := (w-i1)*(1/2+(i1-i2)/(2*tau))*(1-(Pn-Pr)/(1-delta))+(s-i1-Crr)*(1/2+(i1-i2)/(2*tau))*((Pn-Pr)/(1-delta)-(-beta*i1*upsilon+Pr)/delta)+Ce*rho0*(((Pn-Pr)/(1-delta)-(-beta*i1*upsilon+Pr)/delta)*eta+1-(Pn-Pr)/(1-delta))

(w-i1)*(1/2+(1/2)*(i1-i2)/tau)*(1-(Pn-Pr)/(1-delta))+(s-i1-Crr)*(1/2+(1/2)*(i1-i2)/tau)*((Pn-Pr)/(1-delta)-(-beta*i1*upsilon+Pr)/delta)+Ce*rho0*(((Pn-Pr)/(1-delta)-(-beta*i1*upsilon+Pr)/delta)*eta+1-(Pn-Pr)/(1-delta))

 (2)
> 

diff(Pi1, i1) = 0

-(1/2+(1/2)*(i1-i2)/tau)*(1-(Pn-Pr)/(1-delta))+(1/2)*(w-i1)*(1-(Pn-Pr)/(1-delta))/tau-(1/2+(1/2)*(i1-i2)/tau)*((Pn-Pr)/(1-delta)-(-beta*i1*upsilon+Pr)/delta)+(1/2)*(s-i1-Crr)*((Pn-Pr)/(1-delta)-(-beta*i1*upsilon+Pr)/delta)/tau+(s-i1-Crr)*(1/2+(1/2)*(i1-i2)/tau)*beta*upsilon/delta+Ce*rho0*beta*upsilon*eta/delta = 0

 (3)
> 

solve(%, i1)

-(1/3)*(Crr*beta*delta*upsilon-beta*delta*i2*upsilon-beta*delta*s*upsilon+beta*delta*tau*upsilon-Crr*beta*upsilon+beta*i2*upsilon+beta*s*upsilon-beta*tau*upsilon-delta*Pr+delta^2-(6*Ce*beta^2*delta^2*eta*rho0*tau*upsilon^2-12*Ce*beta^2*delta*eta*rho0*tau*upsilon^2+6*Ce*beta^2*eta*rho0*tau*upsilon^2+Crr^2*beta^2*delta^2*upsilon^2+Crr*beta^2*delta^2*i2*upsilon^2-2*Crr*beta^2*delta^2*s*upsilon^2-Crr*beta^2*delta^2*tau*upsilon^2+beta^2*delta^2*i2^2*upsilon^2-beta^2*delta^2*i2*s*upsilon^2-2*beta^2*delta^2*i2*tau*upsilon^2+beta^2*delta^2*s^2*upsilon^2+beta^2*delta^2*s*tau*upsilon^2+beta^2*delta^2*tau^2*upsilon^2-2*Crr^2*beta^2*delta*upsilon^2-2*Crr*beta^2*delta*i2*upsilon^2+4*Crr*beta^2*delta*s*upsilon^2+2*Crr*beta^2*delta*tau*upsilon^2-2*beta^2*delta*i2^2*upsilon^2+2*beta^2*delta*i2*s*upsilon^2+4*beta^2*delta*i2*tau*upsilon^2-2*beta^2*delta*s^2*upsilon^2-2*beta^2*delta*s*tau*upsilon^2-2*beta^2*delta*tau^2*upsilon^2+Crr^2*beta^2*upsilon^2+3*Crr*Pn*beta*delta^2*upsilon-2*Crr*Pr*beta*delta^2*upsilon+Crr*beta^2*i2*upsilon^2-2*Crr*beta^2*s*upsilon^2-Crr*beta^2*tau*upsilon^2+2*Crr*beta*delta^3*upsilon-3*Pn*beta*delta^2*s*upsilon+3*Pn*beta*delta^2*upsilon*w-Pr*beta*delta^2*i2*upsilon+2*Pr*beta*delta^2*s*upsilon+Pr*beta*delta^2*tau*upsilon-3*Pr*beta*delta^2*upsilon*w+beta^2*i2^2*upsilon^2-beta^2*i2*s*upsilon^2-2*beta^2*i2*tau*upsilon^2+beta^2*s^2*upsilon^2+beta^2*s*tau*upsilon^2+beta^2*tau^2*upsilon^2+beta*delta^3*i2*upsilon-2*beta*delta^3*s*upsilon-beta*delta^3*tau*upsilon+3*beta*delta^3*upsilon*w-3*Crr*Pn*beta*delta*upsilon+Crr*Pr*beta*delta*upsilon-4*Crr*beta*delta^2*upsilon+3*Pn*beta*delta*s*upsilon-3*Pn*beta*delta*upsilon*w+2*Pr*beta*delta*i2*upsilon-Pr*beta*delta*s*upsilon-2*Pr*beta*delta*tau*upsilon+3*Pr*beta*delta*upsilon*w-2*beta*delta^2*i2*upsilon+4*beta*delta^2*s*upsilon+2*beta*delta^2*tau*upsilon-6*beta*delta^2*upsilon*w+Crr*Pr*beta*upsilon+2*Crr*beta*delta*upsilon+Pr^2*delta^2-Pr*beta*i2*upsilon-Pr*beta*s*upsilon+Pr*beta*tau*upsilon-2*Pr*delta^3+beta*delta*i2*upsilon-2*beta*delta*s*upsilon-beta*delta*tau*upsilon+3*beta*delta*upsilon*w+delta^4-2*Pr^2*delta+4*Pr*delta^2-2*delta^3+Pr^2-2*Pr*delta+delta^2)^(1/2)+Pr-delta)/(beta*upsilon*(-1+delta)), -(1/3)*(Crr*beta*delta*upsilon-beta*delta*i2*upsilon-beta*delta*s*upsilon+beta*delta*tau*upsilon-Crr*beta*upsilon+beta*i2*upsilon+beta*s*upsilon-beta*tau*upsilon-delta*Pr+delta^2+(6*Ce*beta^2*delta^2*eta*rho0*tau*upsilon^2-12*Ce*beta^2*delta*eta*rho0*tau*upsilon^2+6*Ce*beta^2*eta*rho0*tau*upsilon^2+Crr^2*beta^2*delta^2*upsilon^2+Crr*beta^2*delta^2*i2*upsilon^2-2*Crr*beta^2*delta^2*s*upsilon^2-Crr*beta^2*delta^2*tau*upsilon^2+beta^2*delta^2*i2^2*upsilon^2-beta^2*delta^2*i2*s*upsilon^2-2*beta^2*delta^2*i2*tau*upsilon^2+beta^2*delta^2*s^2*upsilon^2+beta^2*delta^2*s*tau*upsilon^2+beta^2*delta^2*tau^2*upsilon^2-2*Crr^2*beta^2*delta*upsilon^2-2*Crr*beta^2*delta*i2*upsilon^2+4*Crr*beta^2*delta*s*upsilon^2+2*Crr*beta^2*delta*tau*upsilon^2-2*beta^2*delta*i2^2*upsilon^2+2*beta^2*delta*i2*s*upsilon^2+4*beta^2*delta*i2*tau*upsilon^2-2*beta^2*delta*s^2*upsilon^2-2*beta^2*delta*s*tau*upsilon^2-2*beta^2*delta*tau^2*upsilon^2+Crr^2*beta^2*upsilon^2+3*Crr*Pn*beta*delta^2*upsilon-2*Crr*Pr*beta*delta^2*upsilon+Crr*beta^2*i2*upsilon^2-2*Crr*beta^2*s*upsilon^2-Crr*beta^2*tau*upsilon^2+2*Crr*beta*delta^3*upsilon-3*Pn*beta*delta^2*s*upsilon+3*Pn*beta*delta^2*upsilon*w-Pr*beta*delta^2*i2*upsilon+2*Pr*beta*delta^2*s*upsilon+Pr*beta*delta^2*tau*upsilon-3*Pr*beta*delta^2*upsilon*w+beta^2*i2^2*upsilon^2-beta^2*i2*s*upsilon^2-2*beta^2*i2*tau*upsilon^2+beta^2*s^2*upsilon^2+beta^2*s*tau*upsilon^2+beta^2*tau^2*upsilon^2+beta*delta^3*i2*upsilon-2*beta*delta^3*s*upsilon-beta*delta^3*tau*upsilon+3*beta*delta^3*upsilon*w-3*Crr*Pn*beta*delta*upsilon+Crr*Pr*beta*delta*upsilon-4*Crr*beta*delta^2*upsilon+3*Pn*beta*delta*s*upsilon-3*Pn*beta*delta*upsilon*w+2*Pr*beta*delta*i2*upsilon-Pr*beta*delta*s*upsilon-2*Pr*beta*delta*tau*upsilon+3*Pr*beta*delta*upsilon*w-2*beta*delta^2*i2*upsilon+4*beta*delta^2*s*upsilon+2*beta*delta^2*tau*upsilon-6*beta*delta^2*upsilon*w+Crr*Pr*beta*upsilon+2*Crr*beta*delta*upsilon+Pr^2*delta^2-Pr*beta*i2*upsilon-Pr*beta*s*upsilon+Pr*beta*tau*upsilon-2*Pr*delta^3+beta*delta*i2*upsilon-2*beta*delta*s*upsilon-beta*delta*tau*upsilon+3*beta*delta*upsilon*w+delta^4-2*Pr^2*delta+4*Pr*delta^2-2*delta^3+Pr^2-2*Pr*delta+delta^2)^(1/2)+Pr-delta)/(beta*upsilon*(-1+delta))

 (4)
> 

simplify(%)

Error, (in simplify/do) invalid simplification command

  
 

``

Download Q_Simplify.mw

Problem solving an inequality...

Andiguys 85 Maple 2019
solve inequality parametric
September 20 2025
1 1

I need to isolate i1​ and move the remaining terms to the other side. However, I’m encountering an error while doing this.

Note: All parameters are non-negative (positive or equal to zero).

Attaching sheet: Question_Isolate_i1.mw

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