Maple 2019 Questions and Posts

These are Posts and Questions associated with the product, Maple 2019

Dear everyone,

Ive been looking at this problem ive got, but i cant find out what would make it work. I can put numbers in a matrix, i can solve 3 unknowns with 3 equations. But now there is a variable, and the variable causes the solution to give either: 1 solution, no solution, or more than one solution. 

I can "brush the matrix" as they say it in Dutch, but im learning Maple so it can go a lot faster than manual labor. So is there a way to do it with Maple? 

Figure 4.1 gives from left to right: 1 solution, no solution, and an indefinite amount of solutions.

Questions: For what value of p, a. gives 1 solution? b. gives no solution? c. gives more than 1 solution?

Now i got Maple to tell me how much p x1, x2, and x3 was, but its not bringing me anywhere to where i can get to a solution. 

A manual method is given in this example. Manual is way way to slow for what i need to achieve, ive got some large big books with mechanics, dynamics, statics, fluid mechanics, concrete calcutions, chemistry etc. waiting for me. I can never achieve that manually in the same time as i could do it with maple. :S 

#example of how to do a solve of a matrix with 3 variables:

stelsel := {x1+x2+x3 = 4, 3*x1+x2-5*x3 = -10, 3*x1+2*x2-x3 = 1}

{x1+x2+x3 = 4, 3*x1+x2-5*x3 = -10, 3*x1+2*x2-x3 = 1}


solve(stelsel, {x1, x2, x3})

{x1 = -7+3*x3, x2 = 11-4*x3, x3 = x3}


#now the example number 15

stelsel := {(2-p)*x2+x3 = 2, -x1+2*x2+(2-p)*x3 = 0, (1-p)*x1+2*x2+2*x3 = p+3}

{(2-p)*x2+x3 = 2, -x1+2*x2+(2-p)*x3 = 0, (1-p)*x1+2*x2+2*x3 = p+3}


solve(stelsel, {x1, x2, x3})

{x1 = -(p^2-6)/(p^2-4*p+4), x2 = -(2*p-5)/(p^2-4*p+4), x3 = 1/(-2+p)}



Thank you!


The Function

Download Mapleprimes_Question_Book_2_Paragraph_4.2_Example_15.mw

Can someone help me write the program for this equation?
I really need this program.
With respect


I hava a recursive formula with variable n. The answer has the variable n and also N1.  What doe N1 mean?


Kindly help me to find the coefficients from the equation. I have attached the MAPLE file here.

Thank You 

It may seem like a stupid question, but why is the first answer not complete, but the second imput is the same as what the book states?

I know you dont need to be able to read Dutch to understand that A = amplitude (amplitude), Omega = Hoekfrequentie (Angular frequency), and Varphi= Fasehoek (phase angle). 

They state that fc(0)= A*e^i*varpi, but it clearly shows that the equation on the left of the equal sign gives a "2" and on the right it gives "2+ 2*i*sqrt3".

Why is this so? It does not make things more easy if you can make "mistakes" like that by just asking the answer, but maple spits out half an answer... 

He thanks a lot guys!


The Function 

I scanned my math books, i like it, i can search in the book now with the "ctrl+f" function in Adobe reader. Get a scanner. Mine is a Canon Lide 400. Not regretting it.. :) 
Download Mapleprimes_Book_2_Question_3.6.mw

omega := 5



`&varphi;` := (1/3)*Pi



A := 4




proc (t) options operator, arrow, function_assign; A*cos(omega*t+varphi) end proc












Download Mapleprimes_Book_2_Question_3.6.mw

What is the procedure to add global optima package in maple?

Dear power users, could someone be so kind to help me out with this file and give me some explanation on what I did wrong?

QuestionMaplePrimes.mw Thank you for you time and help

I am still learning Maple and so I would like to rely on you power users to help me out. I probably doing something which is not allowed or not using the best method. I would appreciate any advice. Thank you in advance    ProcQuestion.mw 

Fitting procedures in Maple are self explaning and easy to perform. However, I was wondering if it is possible to fit data vectors with units. For example one vector would have units of seconds and the other units of length. Thank you for your help.

Maple code for finding optimum maximum value of function TOTP given below when D is kept in the range of 300 to 2000?Also give maple code to find 3Dplot to determine the convexity of function TOTP with respect to y and Sr?

I want the resulting shape of the 3D matrix M (ٍExcel file) to be placed in below grids codes.
The range of x and y is between 0 and 1 and the range of z is 1/1 e-4 to 1/1 e-10.




grids := proc (M, x_min, x_max, y_min, y_max) local z_min, z_max, plot_f, xz, yz, xy; z_min := 0.11e-6; z_max := 0.1e-2; plot_f := plot3d(M, x = x_min .. x_max, y = y_min .. y_max); xz := plot3d([x, y_min, z], x = x_min .. x_max, z = z_min .. z_max, style = line, color = blue, thickness = 0, grid = [6, 6]); yz := plot3d([x_min, y, z], y = y_min .. y_max, z = z_min .. z_max, style = line, color = blue, thickness = 0, grid = [6, 6]); xy := plot3d([x, y, z_min], x = x_min .. x_max, y = y_min .. y_max, style = line, color = blue, thickness = 0, grid = [6, 6]); return plots:-display(plot_f, xz, yz, xy, lightmodel = none, tickmarks = [6, 6, 6], labels = [x, y, "Error"], labeldirections = [horizontal, horizontal, vertical], axes = frame, orientation = [45, 70, 0], view = 0.11e-6 .. 0.1e-2) end proc

grids(M, 0, 1, 0, 1)

Warning, expecting only range variables [x, y] in expression M to be plotted but found name M






Download eeeeeee.mw

Perhaps a silly question but is it possible to stack two dataframe columns? When I use the Vector command the columns are stacked but nested.

Thank you for your help

Could any one please guide me how to show this solution by using Newton Raphson method. I need to show this solution step by step as shown in example.

Hi Community, I have solved the some basic expression by using built in command to get solution. Now i am interested to view the solution stp by step to show  my students of grade 10.


t := x^6+2*x^5-3*x+2+(2*x^6-4*x+8)



p := 2*x^2-x-10






s := 2*x^2-x-10



solve(s = 0, {x})

{x = 5/2}, {x = -2}


sqrt(x-4) = 4

(x-4)^(1/2) = 4


solve(sqrt(x-4) = 4, {x})

{x = 20}


s := (x^2-9)/(x^2-2*x-15)













Solving a system of equations:

x+2*y = 4

x+2*y = 4


3*x+4*y = 6

3*x+4*y = 6


solve({x+2*y = 4, 3*x+4*y = 6}, {x, y})

{x = -2, y = 3}


abs(3*x+3) = 12

3*abs(x+1) = 12



solve(abs(3*x+3) = 12, {x})

{x = 3}, {x = -5}



Download Help_to_view_solution_step_by_step.mw

I know you can filter a dataframe by putting constraints on the numeric columns. However, I would like to sort and filter based upon a given string in a column, is this possible? I cannot immediately find this in the help files. Thank you for your assistance.QuestionDataFrame.mw

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