I have the function which I run well in Maple V
but in maple 15 .It's wrong. How can it be? and please help me to edit it.

for i from 0 to 15 do
t:=1+i/16;
p.i:=plot(sin(x*t),x=-10..10,axes=none):
od:
display(array(1..4,1..4,[[p0,p1,p2,p3],[p4,p5,p6,p7],
[p8,p9,p10,p11],[p12,p13,p14,p15]]));

Hi everyone,

I guess the question I am asking is quite common, however I am still not able to figure it out. I have several (right now three) non-linear inequalities. Given these inequalities, I try to plot them in one graph and then color the different areas with different colors. It would be also ok, if just the area where all inequalities hold is plotted. To do this I have already tried several things. With implicitplot and transparency it is generally working, but...

I have a 6 x 6 matrix. I want to employ Cramer's rule to solve Gx=Θ. I need to sequently substitute column Vector Θ into the matrix columns. I can't get this to work. I have only being using Maple for a couple of weeks so still finding my way.

myf:=(mu,sigma)->int(exp(-(x-mu)^2/2/sigma^2)/sigma/sqrt(2*Pi)/(1+exp(-x)),x=-infinity..infinity);

plot3d('myf(mu,sigma)',mu=-5..5,sigma=0.5..10);

This plot was never created. I think it's taking too long to evaluate it when it's divegent.

Hi all,

For my research purpose, I need to integrate this function. I understand that there maybe values for which this integration is divegent. But is there a way to look into it? Say creat...

how to write a procedure to ceiling a number such as 3.5 to 4

I have a set of multi variate polynomial  equations. I need to setup a matrix [G][x]=[Θ]  Θ is a function of c₁ and c₂ up to 4th order terms

 My problem x=[c₁⁵, c₁⁴c_{2 ,} c₁³c₂² , c₁²c₂³ , c₁c₂⁴ , c₂⁵ ] these 6 5th order terms...

Hi,

I'm trying to plot a few phase portraits for this four equation system but maple wont let me...

> restart;

> s := 10; d[T] := 0.2e-1; k1 := 2.4*10^(-5); k2 := 3*10^(-3);
> N := 5; delt := .24; c := 2.4; T0 := 1; 

with(DEtools); 

with(plots);

[INSERT YOUR CODE HERE BY COPY-PASTING IN 1-D FORMAT]

Can someone please help me? Thanks

Hi everyone,

I want to create a Gaussian PDF so I need to calculate Determinant(sigma) with sigma the covariance matrix of a gaussian variable.

If we call this variable alpha (which is a 12 dimension vector and represents the noise in a discrete dynamical equation), then sigma_ij=ExpectedValue(alpha_i*alpha_j)-ExpectedValue(alpha_i)*ExpectedValue(alpha_j)

and this is zero most of the time! So the covariance matrix is singular and the determinant is zero. 

Hello,

Could you please help me with the following system of equations:

> restart; with(student);
> Z[0] = 377;
> solve({Z = 1/(j*w*C[1]+1/(j*w*L[1])+1/R)+1/(j*w*C[2]+1/(j*w*L[2])), C[1] = w[c]*(w[0]^2-w[c]^2)*(w[2]^2-w[1]^2)/(2*Z[0]*(w[1]^2-w[c]^2)*(w[0]^2-w[1]^2)), C[2] = w[c]*(w[0]^2-w[c]^2)*(w[2]^2-w[1]^2)/(2*Z[0]*(w[1]^2-w[c]^2)*(w[2]^2-w[c]^2)*(w[2]^2-w[0]^2)), L[1] = 1/(w[1]^2*C[1]), L[2] = 1/(w[2]^2*C[2]), R[1] = subs(w = w[1], 2*Z[0]*(1-S[21...

I'm trying to write a program that solves sudoku's using a Groebner basis. I introduced 81 variables x₁ to x₈₁, this is a linearisation of the sudoku board.

The space of valid sudokus is defined by:

for i=1,…,81 : F_i=(x_i−1)(x_i−2)⋯(x_i−9) This represents the fact that all squares have integer values between 1 and 9.

for all x_i and x_j which...

circle_line_intersec.mw

i'm trying to write some code that will output an angle phi when a null event is reached.

see worksheet

Hello,

is there a way to activate the "undo" command after executing the entire worksheet? 

Before executing every change can be undone, but since I press the execute button 

often, I loose my chance to undo.


thanks

Does anyone know the release date of Maple 16?

A common example to emphasize that it is not OK to bring absolute values inside the integral compares

abs( int( cos(n*x), x=0..Pi ) ) asuming n::integer

and

int( abs( cos(n*x) ), x=0..Pi ) assuming n::integer

Maple correctly formulates the first to 0. But the second expression gives it more trouble, returning two messages:

Warning, unable to determine if (1/2)*Pi*(1+2*_Z7)/n is between 0 and Pi; try to use assumptions or use the AllSolutions option
Warning, unable to determine if (1/2)*Pi*(1+2*_Z8)/n is between 0 and Pi; try to use assumptions or use the AllSolutions option

I want to assign the output of a function that has been passed to timelimit. Currently I have to pass, say, X in by reference (as a single element list) and do  timelimit( 0.5, F(X,args) ); where F := proc( X::list ); X[1] := f(args); end proc; --- which is not really desireable. 

More generally I want my proceudre to skip loop iterations that are taking too long.