Maple Questions and Posts

These are Posts and Questions associated with the product, Maple
This is pretty similar to my last question. but I found this maple code on a website that is suppose to find a vertex coloring of a graph G. The output is is supposed to be a list for example like [3, table([y = 1, k = 2, c = 2, m = 3, h = 1, x = 1] where the first part (in this case 3) is the number of colors and 1,2,3 in the second part are the colors to which each vertex is assigned.  However, no matter what graph I run this on I get everything equal to 1. such as [1, table([y = 1, k = 1, c = 1, m = 1, h = 1, x = 1])]. Why is this happening?  
color:=proc(G)
  local i, j, C, U, V, total_used;
  V:=Vertices(G); total_used:=1;
  C[V[1]]:=1;
  for i from 2 to nops(V) do
    C[V[i]]:=0;
  end do;
  for i from 2 to nops(V) do
    U:={};
      for j from 1 to nops(neighbors(V[i], G)) do
      U:=U union C[neighbors(V[i], G)[j]];
       end do;
    j:=1;
    while member(j, U) do
      j:=j+1;
     end do;
    C[V[i]]:=j;
    if j>total_used then
      total_used:=j;
    end if;
   end do;
  [total_used, eval(C)];
end:

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Hi, I'm trying to write a maple procedure to differentiate a function from first principles and so far I have

First_Principle := proc (f); for f do A := simplify((f(x+h)-f(x))/h); Limit(A, h = 0) = limit(A, h = 0) end do end proc

and from there I have no idea where to go. Does anybody have any ideas? Thanks!

How to solve the inequality

with Maple?

My attempts were the following.

Warning, solutions may have been lost

Of course, this works

f(1);
,

but one wishes to describe the solutions in the dependence on the parameter a. Unfortunately, both

and

produce wrong outputs(An SCR has been submitted by me.).

 

 

 

 

 

 

hi..i am a problem with solving following ....please help me ....thanks alot

dsys3 := {10*f2(x)+12*(diff(f1(x), x))+14*f3(x) = 0, 2*(diff(f1(x), x, x))+4*(diff(f2(x), x))+6*(diff(f3(x), x)) = 0, 16*(diff(f3(x), x, x, x, x))+19*(diff(f3(x), x, x))+22*(diff(f1(x), x))+25*f2(x)+27*f3(x)+29*f3(x)+31+32 = 0, f1(0) = 0, f1(1) = 0, f2(0) = 0, f2(1) = 0, f3(0) = 0, f3(1) = 0, ((D@@1)(f1))(0) = 0, ((D@@1)(f1))(1) = 0, ((D@@1)(f2))(0) = 0, ((D@@1)(f2))(1) = 0, ((D@@1)(f3))(0) = 0, ((D@@1)(f3))(1) = 0}; dsol5 := dsolve(dsys3, 'maxmesh' = 500, numeric, range = 0 .. 1, abserr = .1, output = listprocedure); fy3 := eval(f3(x), dsol5); fy2 := eval(f2(x), dsol5); fy1 := eval(f1(x), dsol5)

ERROR.mw

Hello people in Mapleprimes,

 

I want to know how to use apply rule in the following problem.

Please tell me how to do about this.

applyrule(2*F(K,L)=F(2*K,2*L),2*F(K,L));

returns F(2*K,2*L), which is right.

But, what I want to do is to apply the rule with holding n as general variable of real number.

But, what I can get through 

applyrule(n*F(K,L)=F(n*K,n*L),2*F(K,L));

is only 2*F(K,L) not F(2*K,2*L).

 

What should I write additinally to the above to have Maple calcurate and produce the outcome as F(2*K,2*L), F(3*K,3*L) and so on?

 

Best wishes.

 

Taro

 

 

I'm brand new to Maple and was assigned a problem to modify a code provided by my professor to incorporate variable window size. However, I don't know where to begin or what I'm doing. I've attached the link to the problem below. Plz help.  NA1_Project_IDW_01.2014_Fall.pdf

Hi, I've written some matrix computation in maple 18 . I wanna open this file in maple 16 ? how is it possible ? any help is appreciated in advance.

Hello, all.

I would like to plot a weighted graph.

Edge weights are floating point numbers (for example, 1,0; 2,0, 3,0, ...).

I tried:

>M := MATRIX([[0., 2.0, 1.0], [2.0, 0., 3.0], [1.0, 3.0, 0.]]);

> with(GraphTheory):
> G := Graph(undirected,weighted,M);

But it doesn't work.

Of course, I can take the edge weight and multiply it by 10 or 100.
May be somebody could provide a more simple solution.

I'd like to pay attention to the recent article "The Misfortunes of a Trio of Mathematicians Using Computer Algebra Systems. Can We Trust in Them?"

In particular, the authors consider the integral

int(abs(exp(2*Pi*Ix)+exp(2*Pi*I*y)),[x=0..1,y=0..1]),

stating "Both Mathematica and Maple return zero as the answer to this calculation. Yet this cannot be correct, because the integrand is clearly positive and nonzero in the indicated region". Unfortunately, they give only the Mathematica command to this end.

Of course, the integral under consideration is complicated so the the simple-minded trials

int(evalc(abs(exp((2*Pi*I)*x)+exp((2*Pi*I)*y))), [x = 0 .. 1, y = 0 .. 1]);

and

VectorCalculus:-int(evalc(abs(exp((2*Pi*I)*x)+exp((2*Pi*I)*y))), [x,y]=Rectangle( 0 .. 1, 0 .. 1));

fail. However,this can be found with Maple (I think with Mathematica too.) in such a way.

 

A := evalc(abs(exp((2*Pi*I)*x)+exp((2*Pi*I)*y)))

((cos(2*Pi*x)+cos(2*Pi*y))^2+(sin(2*Pi*x)+sin(2*Pi*y))^2)^(1/2)

(1)

NULL

B := simplify(A, trig)

(2*cos(2*Pi*x)*cos(2*Pi*y)+2+2*sin(2*Pi*x)*sin(2*Pi*y))^(1/2)

(2)

op(B)[1]

2*cos(2*Pi*x)*cos(2*Pi*y)+2+2*sin(2*Pi*x)*sin(2*Pi*y)

(3)

combine(op(B)[1], x)

2*cos(2*Pi*x-2*Pi*y)+2

(4)

C := eval(B, op(B)[1] = combine(op(B)[1], x))

(2*cos(2*Pi*x-2*Pi*y)+2)^(1/2)

(5)

int(C, [x = 0 .. 1, y = 0 .. 1])

4/Pi

(6)

``

 

Download int.mw

 

 

Hello,

 

I have the following condition with two unknowns: t1 and t3:

-N*exp(Q1*alpha*eta*t1/(N*w))*exp(-(((N*w-z)*t1^2+((-N*w+z)*t3+2*Q1)*t1+(1/2)*t3*(t3*(N*w-z)-2*Q1))*alpha-2*N*w*C[max]*(t1-(1/2)*t3))*eta/(N*w))*S1*upsilon*w+N*exp(Q1*alpha*eta*t1/(N*w))*exp(-(((N*w-z)*t1^2+((-N*w+z)*t1+2*Q1)*t1+(1/2)*t1*((N*w-z)*t1-2*Q1))*alpha-2*N*w*C[max]*(t1-(1/2)*t1))*eta/(w*N))*S1*upsilon*w+K1^2*exp((1/2)*t1^2*alpha*eta*z/(N*w))*exp(-(1/2)*t1^2*alpha*eta)*exp(t1*eta*C[max])*alpha*eta*t1*z-K1^2*exp((1/2)*t1^2*alpha*eta*z/(N*w))*exp(-(1/2)*t1^2*alpha*eta)*exp(t1*eta*C[max])*alpha*eta*t3*z+K1*exp((1/2)*t1^2*alpha*eta*z/(N*w))*exp(-(1/2)*t1^2*alpha*eta)*exp(t1*eta*C[max])*S1*alpha*eta*t1*z-K1*exp((1/2)*t1^2*alpha*eta*z/(N*w))*exp(-(1/2)*t1^2*alpha*eta)*exp(t1*eta*C[max])*S1*alpha*eta*t3*z = 0

I know that this condition holds when t1=t3. Does there exist an additional solution for t1 and t3 which satisfies this condition?

Thanks,

Dmitry

error in( dsolve/numeric/bvp) unable to achieve the requested accuracy of 0.1e-5 with maximum 128 point mesh (was able to get 0.22e-4), consider increasing `maxmesh` or using larger `abserr`

 

The above is the error message displayed by maple 17. How do I correct this.

Thank you.

 

Adeniyi Michael

M:=Array([[a+2*b,b],[x1+y1,z1+z2]]);
pars:=indets(M);
npars:=numelems(pars);

myRand:=RandomTools[Generate](float(range=-3..3),makeproc=true):

set1:={seq(pars[i]=myRand(),i=1..npars)};
numM:=subs(set1,M);
LinearAlgebra:-Rank(numM);

is there a way to make sure that the random values generated from myRand(), subs into M, to make sure that each cell of M is between 0 and 1?

Basically, what I need is being able to simulate some values, subject to each cell of M is between 0 and 1, and find the rank of M. I want to do that efficiently 20 times (or more possibly). Those values that make the cells out of 0 and 1 do not count as 1 of the 20 simulations.

 

Thanks,

 

casper

 

 

Mytest:=module()
    option package;
    
    export
        mymain
        ;
        
        
    # local a,b,c;

    uses LinearAlgebra;
    
    interface(rtablesize=infinity);
    
    
    mymain:=proc(n::integer)

        local ans;
        
        ans:=Vector(n);

        return ans;

    end proc;

end module;

Here is a short piece of code to create a Maple package. It runs fine. Is that possible to hide the code from print() ?

 

with(Mytest);

print(mymain); # which displays the source code

 

Could I hide some of the code? Say I want to use the function mymain() for debugging purpose, but I dont want to make it local to the package. Instead I keep it in "export", but I dont want users to see its code.

 

Thanks!

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