It is given 

   xⁿ (n x - n - x) / (x-1)² + x / (x-1)²  , n is a (symbolic) positive integer.

I want to transform it into

n xⁿ⁺¹ / (x-1) - x (xⁿ-1) / (x-1)². 

How is it possible?

I tried the  simplify, convert (parfrac), collect, combine, expand,  with/without assuming.

Thanks in advance.

Hi everybody,

Ever since i updated to maple 2015, the output of calculations display a disproportionate amount of zeros. For instance:

If i write:

2.3*10^(-4)

i get:

0.000230000000000

Is there anyway to make maple NOT display the last 10 zeros? I've tried Tools ->Options ->Precision -> Round screen display to X. But then it rounds all results to that X amount of digits, wich is also anoying. Like, if i set X to be 10, it'll write 3.000000000 instead of just 3.

Hope someone can help me :-)


Anton

Cn ={ 1, n = 0 ,                                                  }

      {Xn−1[sum of] k=0   C(k)C(n−1−k) , otherwise.  }

looking to complete the definition of catalan so that catalan(n) returns Cn whenever n is a non-negative integer. usin g the definition above...any help appreciated

catalan:=
proc(n::TYPE)
description "Print the n'th Catalan number.";
option remember;
---MORE STUFF HERE---
end proc; # catalan

I am working on something where I need to use a stack. In the Maple documentation I noticed there are two different stack implementations. There is "stack" and "SimpleStack". I am curious if anyone has any experience using either of these and if there is any advantage to one over the other. Any suggestions or tips are appreciated.

Thanks,

Steven

Hello everybody

In the attached file, as you can see, 'u' is function of 'thet1(t)' explicitly, But when I want to differentiate from 'u' w.r.t 'thet1(t)', maple returns zero as the answer. How is it possible?

Thanks in advance

d.mw

I have an ODE with L(x,y), which includes partial derivatives of L(x,y) and coefficients y,_y1 and _y1^2. I want to split this equation into seperate equations of these coefficients. So I can solve for the unknown variable L(x,y).

ODE:=diff(L(x,y),x,x)+2*_y1(x)*diff(L(x,y),x,y)+_y1(x)^2*diff(L(x,y),y,y)+y(x)/x*diff(L(x,y),x)+(y(x)*_y1(x)/x+_y1(x))*diff(L(x,y),y)-y(x)/x^2*L(x,y)=0;

Could someone help me? 

I am currently trying to use the coeffs command but not really getting anywhere.

Thank you.

I a working with circuits, and was wondering whether or not it might be possible to shorten the proces of calculating parallel resistors. My idea is that using some symbol, such as || would find the equivalent resistor.

My idea is based on the fact that CrossProduct can also be done using &x command. Like so.

CrossProduct(a,b) = a &x b

So for resistors it would look something like:

Parallel(a,b) = a || b

For those interested the function for parallel resistors would be:

Parallel := (a,b) -> 1/(1/a+1/b);

the binomial coefficient  n k  can be defined recursively as follows for all nonnegative integers n, k:

(n)  = {0,      k>0

(k)  = {1       k=0, k=n

         {(n-1)+(n-1), otherwise.

          (k-1)   (k)

I need to complete a deinition of binom so that m so that binom(n,k) returns  n k  for all n greater than 0, and k greater than or equal to 0 using the definition of the binomial above..Any help appreciated..

binom:=
proc(n::TYPE1,k::TYPE2)
description "Compute a binomial coefficient";
option remember;
---MORE STUFF HERE---
end proc; # binom

I can calculate the quotient and remainder (r1) of a polinom (p1) divided by another (p2).

Unfortunately, I can't figure out how to divide r1 with p2, so that I get negative powers as well.

For example:

p1 = x^2+3

p2 = x+2

(x^2+3):(x+2) = x, and the remainder is: (-2x+3)

-----------

(-2x+3):(x+2) = -2, and the remainder is: (-1)

-----------

(-1):(x+2) = -x^-1, and the remainder is: (2x^-1)

-----------

(2x^-1):(x+2) = 2x^-2

...

As a result I get:

p1/p2 = x + -2 - x^-1 + 2x^-2 and so on...

How can I achieve this?

How does one explain this? 

Is this not a valid way for creating a floating-point matrix?
Otherwise, how do I explain the wrong result here?

-- Regards,

Franky

I am having trouble removing assumptions that are stored within expresssions.

Example code:

assume(l1>0): # this assumptions later helps to find a solution for a geometric problem with two four-bar-linkages

a := sqrt(l1);

save a, "test.m";

restart;

read "test.m"

a; # the assumptions are stored within the saved data

l1:='l1'; # try to remove the assumption

a; # assumption in a still existing

subs({l1=2}, a); # nothing happens: I can not access l1 any more

subs({l1~=2}, a); # This does not work either, nothing changes in a

So my question is: How do I remove the assumption within a stored expression?

My main problem lies in the handling of the expression with assumptions. At some point, I want to generate Matlab code, and the codegen-command gives me:

Warning, the following variable name replacements were made: l1~ -> cg

Hi all

I have  a simple question in export as eps format in Maple. i want the converted eps file with no box, but when i use export as eps by right click on plotted figure in Maple and then select " Export As--> Encapsulated PostScript(EPS)...", the below mentioned box(as in sample attached picture) will appear. How can I remove it? The Sample picture is attached. 

I will be grateful of any guidance.

Thanks in advance

Mahmood   Dadkhah

Ph.D Candidate

Applied Mathematics Department

I'm trying to find lypunov exponent for this  system of ODEs. I know I need to take the Jacobian but not sure if it's possible the way it's currently defined. If anyone could provide insight it would be much appreciated.

Eqns:= diff(omega(t),t)=-(G*MSat*beta^(2)*(xH(t)*sin(theta(t))-yH(t)* cos(theta(t)))*(xH(t)*cos(theta(t))+yH(t)*sin(theta(t))))/((xH(t)^(2)+yH(t)^(2))^(2.5)),diff(theta(t),t)=omega(t), diff(xH(t),t)=vxH(t),diff(vxH(t),t)=-(G*M*xH(t))/((xH(t)^(2)+yH(t)^(2))^(1.5)),diff(yH(t),t)=vyH(t),diff(vyH(t),t)=-(G*M*yH(t))/((xH(t)^(2)+yH(t)^(2))^(1.5)): ;

ICs := omega(0) = omega0, theta(0) = theta0, xH(0) = a*(1+e), yH(0) = 0, vxH(0) = 0, vyH(0) = sqrt(G*M*(1-e)/(a*(1+e)));

I want the exponent for omega, I  procedure that takes some initial conditions, changing just w0, and computes the long term value of omega. This plots a sort of bifurcation diagram. I'd like an estimate of the exponent to compare what I see. 

thanks for the help

ft

Hello,

I want to compute powers of the Laplace-beltrami operator in some surface (e.g. cylinder):

https://en.wikipedia.org/wiki/Laplace_operator#Coordinate_expressions

and evaluate it for a given scalar function on the surface (e.g. a function on the cylinder).  I'm wondering if I only have to write the laplace-beltrami operator and then compute a simple power of it, or if I have to take care and compute the powers of the Laplace-beltrami operator first and then evaluate at the function on the cylinder. If the second option is the correct one (I think so), how can I compute that with maple? There is some trick way to compute powers of differential operators?

Thanks,

Fernando

Variable exists but is not shown when using save/read with extension .m

My example maple code is

 

a:=b^2:

save a, "test1.m"

restart:

read "test1.m"

a;

after the read command, I can access the variable, but it is not shown under "Variables".

This lead to some confusion when debugging the worksheet. Can I change this somehow?

Using the input type file format is not a solution, since then reading takes forever for complicated expressions.

Further, in the read command documentation it says "This functionality is not intended for end users" for saving the file as .m. What does that mean?