How to get rid of the boundary

display(ellipse([0, 0], 2, 1, filled=true, color = red),size=[1000,500],axes=none);

or how to make the boundary the same color as the filled region?

I am trying to adapt the code with Direct Search 2 for my needs but do not quite understand the syntaxis :( . I have system with 8 first order but nonlinear odes and 20 parameters but for starters I fix most of them (to estimate time consumption for full calculations etc). The part of the code where it ``breaks'' looks as follows:

#argument
X0:=Vector([24, 36, 48, 60, 72, 84], datatype = float):
#value
Y0:=Vector([13.8e+9, 12.13333333e+9, 10.7e+9, 10.5e+9, 9.8e+9, 10.1e+9], datatype = float):

#so this is the data - time in X0 and corresponding observables (at that time instances) at Y0

par_sol:=dsolve(dsys, numeric, range=0..85,  parameters=[eta_L, L0]);

#parametric numerical solution with eta_L parameter of the model and L0 initial condition to fit

ffit2 := proc(etaLValue, L0Value, tValue) global old_eta, old_L0; local res;
if not [etaLValue, L0Value,tValue]::list(numeric) then
      return 'procname'(args); end if;
if old_eta<>etaLValue and old_L0<>L0Value then
      (old_eta,old_L0) := etaLValue,L0Value;
      par_sol('parameters'=[eta_L=etaLValue,L0=L0Value]);
   end if;
   res:=rhs(par_sol(tValue)[4]); end proc;

# this is just adapted copy of your function

par_sol(parameters=[eta_L=0.004, L0=1.1e10]);

par_sol(84)[4];ffit2(0.004, 1.1e10, 84);

#their output coincide OK; same for another trio of parameters

DS2:=CodeTools:-Usage(
        DirectSearch:-DataFit(ffit2,X0,Y0,t,
                              [ eta_L=0.001 .. 0.1, L0=1.5e10 .. 1.7e10
 #                               
                              ] )
);

#and here it breaks:

Warning, initial point [L0Value = .9, tValue = .9] does not satisfy the inequality constraints; trying to find a feasible initial point
Error, (in DirectSearch:-Search) cannot find feasible initial point; specify a new one

But tValue is a time variable - I integrate over it, it is not a parameter to fit - I evaluate ffit2 at it. So basically ffit2 return exactly the model value which need to be fited with data in Y0 at times specified in X0. I thought it is easier than the other problems I saw in examples with Direct Search 2 and still I can't get through syntax neither with it not with NonlinearFit of core Maple...

I would appreciate if you could point me what I am doing wrong. Just in case I also attach full version of the file.01test.mw

Thank you in advance!

Hello. I want to organize some parameter
F=fsolve(1+x^2=j).

If j=-5, for example, an empty value 'F=' will be returned. How can I write the expression

If F=(void), then action 1, else action 2 end if

The fact is that I just don't know how to write the result (void), that is, the result of 'F ='

Thanks

Hi

I was wondering how one uses maple to solve for variables that comprise the limits of an integral?

X and R are between 0 and 1.

Any thoughts would be greatly appreciated, thanks in advance...!

Download Solvingforlimitsofintegrals.mw

When should i use ->  for a procedure definition and when not ?
In my post i do see examples of  procedures which are made on two different ways.
proc  ..end proc;

Still difficult to get a procedure on two ways 

test:=x->x^2;
Typesetting:-mprintslash([(test := x -> x^2)],[x -> x^2])

test(2);
4

restart;
test:= proc()
local x,a;
a:= x^2;
end ;
Typesetting:-mprintslash([(test := proc () local x, a; a := x^2; end proc)],[
proc () local x, a; a := x^2; end proc])

test(2);
x^2

test(3);
x^2

As you can see with the standard proc definition i getlost with  calculating x^2 

In the past I worked with mathcad where it was very easy to work with units. Now I try to switch to Maple but I am still struggling when I want to implement units. In the simple attached worksheet I try to multiply vector a in [m] with vector b in [cm]. I get an answer in [m] but I cannot convert the answer to another unit. Right clicking allows me to change the unit e.g. to mm but nothing happens in the worksheet. When I use convert, the units are expressed numerical in cm but the vector still shows m. My apologies in advance for this simple questions but I find no way to solve my issue.

CollabExample.mw

Anyone can help me to convert matlab codes to maple, pls, this is my code p

Who deleted my post - "How to factor out specific parts from expression"

Can i make a natural numberline what shows the enumber of primes at each of 1000 numbers  
I have her

0-1000 : 168
1000 -2000: 135

2000-3000 : 127

3000- 4000: 120

4000 -5000 : 119 

then a gap (jump) 

10^7- 1000- 10^7  : 53 

You can see that the "number of primes"  is fluctuating
Can i make a procedure what calculates the latest mersenne prime number ?
Problem is only that there is a theorem: there are arbitrary long series of divisible numbers on the numberline 
There are gaps of length n - 1, where are no primenumbers  in positioned.

The idea is to get a idea of the distribution of primes to make a guess from where to start to find another one? 

Hello, I found this code from Acer works great:

p=floating point number such as 0.003483 

nprintf(`#mn(\"%1.3e\");` , p)

prints a number in Scientific format,    3.483e-03

Perfect.

HOWEVER, What is the #mn please?   Is it a comment, or a MathML function?

Regards, Bill

Dear all, do you know if there is a way to ask Maple and the Physics package to use the bold notation of vectors instead of using arrows? 

Thanks, Kevin

Hi,

I want to solve system of  PDE equations by maple and i dont know how can i write it codes that can solve them for me. Can anyone help me please??!!

Good day.

When I export an animated 3D (surface contour) plot to a gif format, the image is incomplete (please see attached file).

Can anyone suggest a way to reformulate the expressions so the animated plot can be exported to Powerpoint intact?

Thanks for reading!

MaplePrimes_Dec_5.mw