When i trying to solve the BVP the following error will found 

Error, (in fproc) unable to store 'HFloat(1.0141653815612295)+HFloat(0.0020355870386861838)*I' when datatype=float[8]
 

I have attached my worksheet.

Please anyone help me to get solution to this problem.

Thank you so much

Download Main.mw

Hello Maple friends,

I use Explore() often and noticed something today which seems like either a bug or an error on my usage.

I have a long worksheet where I use Explore at one point to show the behavior of an expression relative to one parameter assigned to a slider. Later in the sheet however, I re-assign some of the variables used in that expression and I call Explore again to see how the expression behaves with the different parameters.

The issue is that when I move the slider on the first explore, the result is incorrect because it seems to be using the values of the variables at the end of the worksheet, not the variables at the point the Explore statement exists.

I would expect Explore to make a copy of the stack at the point it gets called such that the result is correct in the context of its location in the worksheet.

Is this the correct behavior and is there a way to make this work as expected? The only workaround I have in mind is to rename the variable names just to make Explore work, which doesn't seem like a great solution.

Thanks.

blessing.mw please i really need your help on this, i have been trying to fix this error for a while now. 

I have function that accept keyword argument. From this function, I need to pass this argument to another function using the same signature and using same name for the keyword. But it is not possible to do. 

Easier to explain with an example.   This is what I want to do

restart;
foo:=proc(n::integer,{ic::`=`:=[]})   
   post_process(n+1,'ic'=ic);
end proc;

post_process:=proc(n::integer,{ic::`=`:= []})
    print("in postprocess, n=",n, "ic=",ic);
end proc;

foo(3,'ic'=(y(0)=5))

Gives 

The problem is that when calling post_process(), using 'ic'=ic it does not work. Currently I have to change the keyword name as workaround, like this

restart;
foo:=proc(A::integer,{ic::`=`:=[]})
   print("in foo, A=",A, "ic=",ic);
   post_process(A,'new_ic'=ic);
end proc;

post_process:=proc(A::integer,{new_ic::`=`:= []})
    print("in postprocess, A=",A, "ic=",new_ic);
end proc;

foo(3,'ic'=(y(0)=5))

Which gives

Now it passed it. I would have liked to keep same keyword name ic in both function signatures instead of coming up with new name.

Is there a way to do that? 

This is not the only problem. The problem with this workaround, is that it does not work when the keyword argument is not passed to the first function. Because now it will use the default values of [].

Hence when calling the post_process() function, it fails due to type mismatch. This now gives an error

restart;
foo:=proc(A::integer,{ic::`=`:=[]})
   print("in foo, A=",A, "ic=",ic);
   post_process(A,'new_ic'=ic);
end proc;

post_process:=proc(A::integer,{new_ic::`=`:= []})
    print("in postprocess, A=",A, "ic=",new_ic);
end proc;

foo(3)

Error, (in foo) invalid input: post_process expects value for keyword parameter new_ic to be of type `=`, but received []

So the way I do this now, is to add an extra check each time, like this

restart;
foo:=proc(A::integer,{ic::`=`:=[]})
   if nargs = 2 then #is ic passed in?     
      post_process(A,'new_ic'=ic);
   else
      post_process(A);
   fi;
end proc;

post_process:=proc(A::integer,{new_ic::`=`:= []})
    print("in postprocess, A=",A, "ic=",new_ic);
end proc;

foo(3)# now it works

But in my actual code, I have more than one keyword argument, and I have to keep checking for correct number of arguments each time, to know which arggument to pass along. 

So far, I did not find an easy way around this.

Any suggestion how to do this better? passing keyword argument with default values? from one function to another without getting into these problems?

Maple 2020.2

Dear All 

I would like to calculate the five first terms of a  polynomial  sequence

I wrote in maple 

sum(x^r*(sum((-1)^s*binomial(r, s)*pochhammer((a+s+1)*d, n), s = 0 .. r))/factorial(r), r = 0 .. n), n = 0 .. 4);

I obtained 

0,0,0,0,0

which seems to be false

where is the problem 

Best regards 

This simple set of integrations works correctly and quickly in Maple 17 and other releases, but not in Maple 2020.

psi(x) := (-1)^v*(alpha*GAMMA(k-v)/v!/GAMMA(k-2*v-1)/GAMMA(k-2*v))^(1/2)*exp(-1/2*k*exp(-alpha*x))*                 (k*exp(-alpha*x))^(1/2*k-v-1/2)*LaguerreL(v,k-2*v-1,k/exp(alpha*x))/binomial(k-v-1,v);

Int(eval(%, [k=30.5, v=j, alpha=2.5])^2, x=-1..infinity) =
   seq(evalf[12](Int(eval(%, [k=30.5, v=j, alpha=2.5])^2, x=-1..infinity)), j=0..5);

Every time that I try this simple integration in Maple 2020 I receive a message "kernel connection lost".  Why???

Hi there,

what's wrong with this example:

ph_ex.mw

?

Thank you

Dear all

I have  Lie commutations for vectors e1, e2, e3, e4, e5, e6 as follow:

[e1, e3] = e3, [e1, e4] = e4, [e1, e5] = e5, [e1, e6] = e6, [e2, e3] = -e5, [e2, e4] = e6, [e3, e5] = e6

for which the command 

Query("Jacobi")

returns the false result, which means, the vectors are not closed under Jacobi's identity. How can I find vector triplets for which Jacobi's identity does not hold?

Please find Maple file.Jacobi_identity.mw

Hey everyone!
I have to solve this nonlinear system of equations . For small N (N=8), I tried to do it using solve but it is run forever. I have choosed \gamma to be equal to Pi/4.
test.mw

I tried to expand by the procedures series() and taylor(), but they compute to O(x¹⁵).

Hi

I have two sets of plots

1. plot([1 - 2*x, -0.6 - 2*x, -1 - 2*x], x = -1 .. 1)

2. smartplot[x, y](map('`=`', [31*y^2 + 0.19*x^2 + 0.34*x*y - 0.38*y - 0.22*x + 0.07, 0.31*y^2 + 0.19*x^2 + 0.34*x*y - 0.38*y - 0.22*x, 0.31*y^2 + 0.19*x^2 + 0.34*x*y - 0.38*y - 0.22*x + 0.02, 0.31*y^2 + 0.19*x^2 + 0.34*x*y - 0.38*y - 0.22*x + 0.07, 0.31*y^2 + 0.19*x^2 + 0.34*x*y - 0.38*y - 0.22*x + 0.11], 0))

How do i combine the two into one plot?

thanks!

R

Why Maple gives this error and is this a known issue?

restart;
pdsolve( [diff(u(x,t),t)=diff(u(x,t),x)*diff(u(x,t),x$2), u(x,0)=0],u(x,t))

Maple 2020.2 with Physics 893 on windows 10.

Dear all, 

I have a time-fractional PDE as follows.  ( denotes Caputo fractional derivative with respect to t) 

for alpha=1, this is a classical PDE and the exact solution is given as follows (in a book)

Question: 

1) for alpha=1, I want to find the L2 errors and L∞ errors in a table. 

2) for alpha=0.5, Can Maple find a solution (numeric or exact)?

MY TRY: (MAPLE 2020.2)

download the code.mw

restart:
with(plots):
PDE:=diff(y(x,t),t)=y(x,t)*diff(y(x,t),x$3)+y(x,t)*diff(y(x,t),x)+3*diff(y(x,t),x)*diff(y(x,t),x$2) ;


#c is an arbitratry constant
c:=4:
exact_sol:=(x,t)->-8*c/3*(cos ((x-c*t)/4))^2;

# I selected initial and boundary conditions as follows
IBC := { y(x,0)=exact_sol(x,0),y(0,t)=exact_sol(0,t),D[1](y)(0,t)=D[1](exact_sol)(0,t),y(1,t)=exact_sol(1,t)};
 	
numeric_sol := pdsolve(PDE,IBC,numeric);

num3d:=numeric_sol:-plot3d(t=0..1,x=0..1,axes=boxed,
            color=[0,0,y]);
exact3d:=plot3d(exact_sol(x,t),t=0..1,x=0..1,axes=boxed);
display(exact3d,num3d);

pdetest(y(x,t)=exact_sol(x,t),PDE,IBC);

Hi

I have a system of pde that it is solved with pdsolve procedure.

This procedure takes a few time, but when I need to do plots, especially 3d plot the software takes a lot of time (several hours).

How can I make plots faster?
Thanks.

The problem: to simplify the expression

for any negative  x  and  y .

Below we see that Maple copes with the task brilliantly (example 1). For example, it presents  sqrt(x*y)  as  sqrt(-x)*sqrt(-y)  and so on. But the same technique, applied only to the numerator of this expression does not give the desired presentation in the form of a square (example 2 and example 3).

restart;
# Example 1
A:=(x+y-2*sqrt(x*y))/(sqrt(-x)+sqrt(-y));
simplify(A) assuming negative;
factor(%,{sqrt(-x),sqrt(-y)});

restart;
# Example 2
B:=x+y-2*sqrt(x*y);
simplify(B) assuming negative;
factor(%,{sqrt(-x),sqrt(-y)});

restart;
# Example 3
B:=x+y-2*sqrt(x*y);
R:=simplify(B) assuming positive;
combine(R) assuming positive;
factor(R,{sqrt(x),sqrt(y)});

                                                   

Two questions:

1. Does anyone know the reasons for this behavior.

2. Does anyone know an easy way to simplify in examples 2 and 3 (without  substitutions  like  x=+-u^2  and  y=+-v^2 and so on,  of course)

Download sqrt.mw