Hi everyone

I have a problem with differentiating an equation. I have the following code:

(sum((x(i)-M)^3, i = 1 .. n))/(n*((sum((x(i)-M)^2, i = 1 .. n))/(n-1))^(3/2));

The values of x(i) is available in Excel and I want to import that. For this case, I copy the column and paste in maple and it seems work fine. But, I want to calculate the differentiate of the summation with respect to x(i) and M and find the answer. I don't know how to write the code appropriately.

In other words, how could I differetiate the following function with respect to x(i) and put the values from excel into it.

(sum((x(i)-M)^3, i = 1 .. n))/(n*((sum((x(i)-M)^2, i = 1 .. n))/(n-1))^(3/2));

Thank you so much for your kind attentions  in advance

I have been working some plots using piecewise, and this seem to always result in graphs with very jagged edges

Example: https://i.imgur.com/ZBOSDsL.png

The function its plotting is this one:

f:=unapply(piecewise(x^2+y^2 <= 1 and x>=0, 4*x*y^2-x^2, undefined),x,y):

Now I assume this happens because of the piecewise part. How do I smoothen the edges?

Hi there,

I am doing an exercise which asked me to perform a taylor expansion for an arbitrary function of 2 variables (x,y) around an arbitrary point (x0,y0). Here's what I've got:
Question.mw

In the above,s and u are any 2 functions of interest.x0 and y0 are the coordinates of the point of expansion.I guess there was something wrong with s and u.What should I type in,in order to make any bi-variate functions as parameters in my procedure?
 

Hello. 

I would like to know if Maple can or cannot evaluate the integral below. It can be done analytically and also in Mathematica. It is not an uncommon type of integral being related to a Fourier transform of a Hankel function.

restart;
assume(alpha>0);assume(beta>0);assume(s>0);
gr:=(beta,r)->(1/8*I)*(-HankelH1(1, beta*r)-(2*I)*BesselK(1, beta*r)/Pi)/beta^2;
int(cos(alpha*s)*gr(beta,s),s=0..infinity);

Many thanks

Download 2dstring.mw

Dear all

Hope everything is fine with everything. I want to draw the graph of the u(x,0.5) and T(x,0.5) for different values of alpha like alpha =0.4,0.6,0.8 while keeping Gr, R and Pr are fixed. Please solve the following problem I shall be vary thankful to you. Thanks in advance

with the following BCs

Is there a way to determine the coordinates of all the vertices of a cuboid using geom3d?

See WC06_Vertices_of_a_Cuboid.mwWC06_Vertices_of_a_Cuboid.mw attached.

The graphic of the cuboid is created with

A:=(cuboid([1,1,2],[3,4,5]), orientation [27,78],lightmodel = light4, shading = none, transparency =.85,scaling = constrained, axesfont = [bold, roman, 18], axes = normal):

And the vertices are self-evident, for example 

B:= pointplot3d({[3,1,5]}, symbol = solidsphere, symbolsize = 18, color = red):

One geom3d ....

geom3d[point](P,1,1,2): geom3d[point(Q,3,4,5): geom3d[distance](P,Q); 

gives the lengths of the diagonal of the box.  Is there a way to get geom3d to list the coordinates of the 8 vertices of a cubeoid?

Can someone show how this can be done in Maple?  I've added the zipped original noisy image .Fig0240(a)(apollo_17_boulder_noisy).zip

Stupid question maybe, but when will the newest version be released or what will the newest version be label wise? When are the newest versions generally released???

Hi, 
I am having a difficulty is running a loop with solve command. I am using a command solve(f(x,alpha)=0, x) in a loop for alpha = 1 by 1 to 10. For some reasons, for some values of alpha, the solve command does not give any solution and hence the program keeps running on. When I interrupt the program at such instance, the remainder of the program is not complete. 

I tried using the try-catch command. I face the same issue. 

Is there a way for me to bypass the solve command when it does not find any solution for a particular alpha and continue with the remainder of the program? I can come back and manually obtain the solution for such alpha values where solve command does not provide an answer.

I would appreciate your help. 

Regards,

Omkar

Does anyone know if there exist a script in JAWS for MapleSoft?

How do I access and assign values given by the solve command

for example

f := unapply(x*(8*x^2+5*x+cos(y)), x, y);

p := solve({diff(f(x, y), x) = 0, diff(f(x, y), y) = 0}, {x, y})

This gives the following

{x = 0, y = (1/2)*Pi}, {x = -1/6, y = 0}, {x = -1/4, y = 0}, {x = -1/2, y = Pi}, {x = 1/12, y = Pi}

now if I type: p[1] I get the following

{x = 0, y = (1/2)*Pi}

Now this isn't very useful. I want to access the "0" and the "(1/2)*Pi". How do I do that?

I have been using random numbers in Maple and want to generate a sum of that random number. I have consider the following

with(stats):

x = random[uniform](10);

and now want 

sum(x_i)^a

where (x_i) is the ith values in x (random array) and "a" is any real number.

in maple 2017 I have enconterd a problem in showing of matrix elements. this error did not exist in maple 2016.

after some mathematical operations with(Linearalgebra)

I have obtained a matrix but maple shows it as below

`Vector(3, {(1) = \`+\`(\`*\`(0.19498673e10, \`*\`(\`^\`(x[1], 3))), \`-\`(\`*\`(0.36539123e10, \`*\`(\`^\`(x[1], 2), \`*\`(x[2])))), \`*\`(0.12514628e10, \`*\`(\`^\`(x[1], 2), \`*\`(x[3]))), \`-\`(\`*\`(7987.1506, \`*\`(\`^\`(x[1], 2)))), \`*\`(0.35170874e10, \`*\`(x[1], \`*\`(\`^\`(x[2], 2)))), \`-\`(\`*\`(0.41418339e10, \`*\`(x[1], \`*\`(x[2], \`*\`(x[3]))))), \`-\`(\`*\`(9187.8615, \`*\`(x[1], \`*\`(x[2])))), \`*\`(0.28788960e10, \`*\`(x[1], \`*\`(\`^\`(x[3], 2)))), \`*\`(2871.4325, \`*\`(x[1], \`*\`(x[3]))), \`-\`(\`*\`(0.95594712e9, \`*\`(\`^\`(x[2], 3)))), \`*\`(0.21616680e10, \`*\`(\`^\`(x[2], 2), \`*\`(x[3]))), \`-\`(\`*\`(16552.293, \`*\`(\`^\`(x[2], 2)))), \`-\`(\`*\`(0.20009067e10, \`*\`(x[2], \`*\`(\`^\`(x[3], 2))))), \`-\`(\`*\`(30447.582, \`*\`(x[2], \`*\`(x[3])))), \`*\`(0.42009564e9, \`*\`(\`^\`(x[3], 3))), \`-\`(\`*\`(42372.407, \`*\`(\`^\`(x[3], 2))))), (2) = \`+\`(\`-\`(\`*\`(0.14713991e11, \`*\`(\`^\`(x[1], 3)))), \`*\`(0.42489026e11, \`*\`(\`^\`(x[1], 2), \`*\`(x[2]))), \`-\`(\`*\`(0.25018214e11, \`*\`(\`^\`(x[1], 2), \`*\`(x[3])))), \`-\`(\`*\`(55498.093, \`*\`(\`^\`(x[1], 2)))), \`-\`(\`*\`(0.34645652e11, \`*\`(x[1], \`*\`(\`^\`(x[2], 2))))), \`*\`(0.52229109e11, \`*\`(x[1], \`*\`(x[2], \`*\`(x[3])))), \`-\`(\`*\`(399927.96, \`*\`(x[1], \`*\`(x[2])))), \`-\`(\`*\`(0.24172439e11, \`*\`(x[1], \`*\`(\`^\`(x[3], 2))))), \`-\`(\`*\`(367829.40, \`*\`(x[1], \`*\`(x[3])))), \`*\`(0.11603445e11, \`*\`(\`^\`(x[2], 3))), \`-\`(\`*\`(0.24618238e11, \`*\`(\`^\`(x[2], 2), \`*\`(x[3])))), \`*\`(163169.71, \`*\`(\`^\`(x[2], 2))), \`*\`(0.24814370e11, \`*\`(x[2], \`*\`(\`^\`(x[3], 2)))), \`-\`(\`*\`(711030.81, \`*\`(x[2], \`*\`(x[3])))), \`-\`(\`*\`(0.64758011e10, \`*\`(\`^\`(x[3], 3)))), \`*\`(427083.52, \`*\`(\`^\`(x[3], 2)))), (3) = \`+\`(\`*\`(0.13627334e11, \`*\`(\`^\`(x[1], 3))), \`-\`(\`*\`(0.67651416e11, \`*\`(\`^\`(x[1], 2), \`*\`(x[2])))), \`*\`(0.94045968e11, \`*\`(\`^\`(x[1], 2), \`*\`(x[3]))), \`*\`(46901.078, \`*\`(\`^\`(x[1], 2))), \`*\`(0.70616015e11, \`*\`(x[1], \`*\`(\`^\`(x[2], 2)))), \`-\`(\`*\`(0.13072873e12, \`*\`(x[1], \`*\`(x[2], \`*\`(x[3]))))), \`-\`(\`*\`(994642.52, \`*\`(x[1], \`*\`(x[2])))), \`*\`(0.41170263e11, \`*\`(x[1], \`*\`(\`^\`(x[3], 2)))), \`-\`(\`*\`(2768390.4, \`*\`(x[1], \`*\`(x[3])))), \`-\`(\`*\`(0.22189949e11, \`*\`(\`^\`(x[2], 3)))), \`*\`(0.67100205e11, \`*\`(\`^\`(x[2], 2), \`*\`(x[3]))), \`-\`(\`*\`(961344.42, \`*\`(\`^\`(x[2], 2)))), \`-\`(\`*\`(0.52533380e11, \`*\`(x[2], \`*\`(\`^\`(x[3], 2))))), \`*\`(2309741.6, \`*\`(x[2], \`*\`(x[3]))), \`*\`(0.23373385e11, \`*\`(\`^\`(x[3], 3))), \`-\`(\`*\`(2708629.4, \`*\`(\`^\`(x[3], 2)))))})`

however its elemets is shown correctly

for example the first element is shown as:

x(1) ^ 3 * 0.194986727121702600e10 + x(1) ^ 2 * x(2) * (-0.365391227687975264e10) + x(1) ^ 2 * x(3) * 0.125146284187383199e10 + x(1) ^ 2 * (-0.798715058230362229e4) + x(1) * x(2) ^ 2 * 0.351708738191481209e10 + x(1) * x(2) * x(3) * (-0.414183393126536083e10) + x(1) * x(2) * (-0.918786154503699254e4) + x(1) * x(3) ^ 2 * 0.287889598946906424e10 + x(1) * x(3) * 0.287143252997207219e4 + x(2) ^ 3 * (-0.955947121705965400e9) + x(2) ^ 2 * x(3) * 0.216166802966718006e10 + x(2) ^ 2 * (-0.165522927641286878e5) + x(2) * x(3) ^ 2 * 

Spawned from here. The code itself is perfectly fine, but if the definition of TD is in the same cell with the rest of the code, TD gives an error. The same definition in a separate cell works.

Download td.mw