## 15 Reputation

19 years, 216 days

## how do i evaluate Vh in the routine belo...

Maple

hall*effect;
hall effect
Vh = B*I/qnd;
I B
Vh = ---
qnd
The Hall voltage represented as VH is given by the formula:    VH=IBqnd  Here,    I is the current flowing through the sensor    B is the magnetic Field Strength    q is the charge    n is the number of charge carriers per unit volume    d is the thickness of the sensor.;

B = 0.5*Unit('T');
q = Unit('e');
B = 0.5 Unit(T)
q = Unit(e)
n = 0.15*100000.*Unit('C')/Unit('L');
d = 10*micron;
15000. Unit(C)
n = --------------
Unit(L)
d = 10 micron
I = 0.1*10^(-5)*Unit('A');
I = 0.000001 Unit(A)
Vh;
Vh

## Why error in simplify?...

Maple 18

why is simplify is making errors - me or maple?

Ec := (1/2)*Kc*(2*Pi*h0/Pi(a0^2+h0^2)-2*Pi*h/Pi(a^2+h^2))^2;
2
1 / 2 Pi h0 2 Pi h \
- Kc |------------- - -----------|
2 | / 2 2\ / 2 2\|
\Pi\a0 + h0 / Pi\a + h //
simplify(%);
2
2 Kc (-h0 + h)

Simplify is erasing the varibles a0 and a. Is there a secret to using simplify?

## How to plot an implicit function...

Maple

I have an implcit function to plot. I can plot it with the parameter but that puts the parameter on the x axis instead of the y axis. What is the best way to present the plot with the parameter on the y axis?

T; R0 := 0.1003183099e-5; T;
/ / -15 -34
- \0.00007363071999 h \3.947841762 10 h + 3.158273412 10

-7 \\// (1/2)
- 3.947841763 10 h R0// |/ 2 -7 \
\\-Pi h + 1.256637062 10 R0/

\
2 / -15 -7 \|
R0 \-1.256637062 10 + 1.256637062 10 R0//
0.000001003183099
1 / 20 /
- --------------------------------- \5.862184047 10 h \4.00
(1/2)
/ 2 -13\
\-Pi h + 1.260637062 10 /

-16 2 -13 -34\\
10 Pi h - 1.260637062 10 Pi h + 3.158273412 10 //
plot(T, h = 0.1e-8 .. 0.10e-7, title = Tension*vs*height*of*dome*above*plane, labels = [m, N/m]);

I would like the plot to be inverted to show the height of the dome as a function of tension;

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