@tuGUTS The x and y are members of a finite group. Yes, every finite group can be represented as a permutation group. (Finding the permutation representation of minimal degree can be difficult (NP-hard I believe--not sure).) That is not the same thing as being a permutation matrix. An n x n permutation matrix represents a permutation on n elements.

A permutation is a member of a permutation group; the permutation is not itself the group.

@tuGUTS The x and y are members of a finite group. Yes, every finite group can be represented as a permutation group. (Finding the permutation representation of minimal degree can be difficult (NP-hard I believe--not sure).) That is not the same thing as being a permutation matrix. An n x n permutation matrix represents a permutation on n elements.

A permutation is a member of a permutation group; the permutation is not itself the group.

@tuGUTS Could you say that again please, using full sentences? I don't understand the connection between the title and the body of your Reply.

@tuGUTS Could you say that again please, using full sentences? I don't understand the connection between the title and the body of your Reply.

@Markiyan Hirnyk 

A randomize() is required if you want different random numbers after a restart. This is what happens if you don't use it:

restart: rand();
                          395718860534
restart: rand();
                          395718860534
restart: randomize(): rand();
                          953915355483

You wrote:

Also I don't see any repetition of randomize() in the code under consideration.

But I know that he is repeating it because that is the only way that he could be having the problem that he describes.

@Markiyan Hirnyk 

A randomize() is required if you want different random numbers after a restart. This is what happens if you don't use it:

restart: rand();
                          395718860534
restart: rand();
                          395718860534
restart: randomize(): rand();
                          953915355483

You wrote:

Also I don't see any repetition of randomize() in the code under consideration.

But I know that he is repeating it because that is the only way that he could be having the problem that he describes.

@jschulzb You wrote:

What does that mean? Is there something wrong with my code, or maple?

A lost kernel connection means that the mathematical "engine" or "kernel" or "server" of Maple has crashed but the GUI continues to run. This always indicates a serious bug in Maple and not a fault in the user's code.

@skullte

First read into the single Matrix M, then break out the columns. It's probably best to avoid using I and D as variable names in Maple as they represent the imaginary unit and the differentiation operator respectively. So I'll use II and DD. (But if you really want to use I and D, there are ways to do that.) Then

InputT, II, DD, Ta:= M[.., 1], M[.., 2], M[.., 3], M[.., 4];

@skullte

First read into the single Matrix M, then break out the columns. It's probably best to avoid using I and D as variable names in Maple as they represent the imaginary unit and the differentiation operator respectively. So I'll use II and DD. (But if you really want to use I and D, there are ways to do that.) Then

InputT, II, DD, Ta:= M[.., 1], M[.., 2], M[.., 3], M[.., 4];

If I run your code at Digits = 15 rather than your Digits = 3, I quickly get a lost kernel connection.

@phil76600 You wrote: I did'nt know ... that f was a special character.

f is not a special character. It's the prime symbol (') (also called an aposthrope or single quote) that is the special character.

@phil76600 You wrote: I did'nt know ... that f was a special character.

f is not a special character. It's the prime symbol (') (also called an aposthrope or single quote) that is the special character.

@goli 

Under that assumption, the expression can be simplified to (I did this part without Maple)

sqrt(1-f)/sqrt(t-t^f)

Then enter that to dsolve:

dsolve(D(y)(t)=sqrt(1-f)/sqrt(t-t^f)) assuming f > 0, 1 > f, t > 1;

It's significantly simpler than the last answer.

@goli 

Under that assumption, the expression can be simplified to (I did this part without Maple)

sqrt(1-f)/sqrt(t-t^f)

Then enter that to dsolve:

dsolve(D(y)(t)=sqrt(1-f)/sqrt(t-t^f)) assuming f > 0, 1 > f, t > 1;

It's significantly simpler than the last answer.

@samiyare 

So sorry. There was one character missing from the code. The constant in the ode should be _C, not C. I corrected the code in the Answer (and added some explanation). Please download again and try it again.