Hi every body:

I have a problem with below function (f(x)), I will calculate values this function with for loop so that values are closer together. for example I will earn 10 or 20 data for this function so that they differences have to be fixed.my means is that I have 10 data like, 50,65,85,90,100,... no 50,100,170,... . that isn't important for me the data increase with constant value but my final data must be closer together. (the maximum number of my data to be taken is 50). 

function is:

f:=(x)->(310*(z+0.5)^0.2)+70

z=[-0.5,0.5]

with regards...

Mehran.

Hi every body:

i will earn the cofficients of q(T),q(T)^2 and (diff(q(T), T, T)) with commonds maple,how?

eq := 324.6463527*(diff(q(T), T, T))+4.012505275*10^11*q(T)+3.589858529*10^12*q(T)^2 = 0;

Hi every body:

i have a second order ode and will convert to two ode of first order with maple,how do this work???

eq := diff(y(x), x, x)+2*y(x)+y(x)^2 = 0

Hi:

i will sole the below non-linear equtions in maple,how?(all initial conditons are zero)

EQ1 := -9.034666667*10^5*Pi^2*q3(t)*q1(t)+3044.230933*Pi*q1(t)*q5(t)+3044.230933*Pi*q1(t)*q4(t)+2.541000000*10^5*q1(t)^3*Pi^4+2.171794873*10^5*q1(t)*Pi^2-2.171794873*10^5*q2(t)*Pi+4.372778665*(diff(q1(t), t, t)) = 0
EQ2 := 54294.87180*q2(t)-54294.87180*q1(t)*Pi-.8371635069*q4(t)*Pi+.8371635069*q5(t)*Pi+1.093194666*q2(t)*Pi^2+0.7054749580e-5*(diff(q2(t), t, t)) = 0
EQ3 := 9.034666667*10^5*q1(t)^2*Pi^2+6.776000000*10^5*Pi^2*q3(t)-2283.173200*q5(t)*Pi-2283.173200*q4(t)*Pi = 0
EQ4 := -1.123134385*10^8*q1(t)*(diff(q1(t), t))+636.6197724-5191.348750*q4(t)-2.035463170*10^7*(diff(q5(t), t))-2.035463170*10^7*(diff(q4(t), t))-5191.348750*q5(t) = 0
EQ5 := .7002817496-29887.90348*q4(t)+29887.90348*q5(t)-135.8992605*(diff(q2(t), t))-7463.364956*(diff(q4(t), t))+7463.364956*(diff(q5(t), t)) = 0

Hi:

I will a write program in maple for plot the function f(x),while asked value n from user at first,then plot function f(x) for each value of n and finally all plots show in one figure only for different value of n,how to do it?

f(x)=1+2*(1+x)^n,x=0..5