#30

llvll=3              u=<4,-4>

-Find the magnitude of the given vector and divide each of the components by that magnitude. That will produce a unit vector that is the same direction of the given vector. Since it wants the magnitude to be equal to 3, multiply each component by 3. Make sure the radicans are out of the denominator. The answer should be a vector in component form.

#48

llvll=3            u=3i+4j

I got a big problem with one kind of integral function. Now, I am using Maple 8 or Maple 11 to get some results from my research topic. However, when I took three times integral like :

f:= Int(exp(-t^2),t = 0 .. infinity)+Int(Int(2*Int(.1*exp(-.25*(u-s-k)^2)*exp(-(-.5*u-.5*s-.5*k+t)^2)*exp(.25*(u-s-k)^2)*exp(-.1*k),k = 0 .. u-s)*exp(-u^2)*u,u = s .. t),t = 0 .. infinity);

After that, I try to draw the grahp of the above equation.

plot(f,s=0..1);

Hi everybody.

I'm using Maple these days to generate C code. More precisely, I use Maple to calculate high order derivatives. For example, I know that :

dt( u(x,t) ) = a(x) * dx( u(x,t) ) + b(x) * dx( p(x,t) )

dt( p(x,t) ) = c(x) * dx( p(x,t) ) + d(x) * dx( u(x,t) )

and I ask Maple to calculate the 5th time-derivative of u using these 2 properties. But in fact, I use 8 variables instead of 2 and PDEs are far more complicated.

Finally, I get thanks to Maple expressions of time-derivatives for my 8 variables.

Hi, I'm traying to maje a double integrate of P(A(t+Deltat),A(t)) , the first one in in untion of dA(t) and the second one is in fuction of dA(t+ DeltaT). How can I indicate in Maple Deltat?  Is it possible to integrate in function of A(t)?

All variables are constant, except A(t) and A(t + Deltat),

> F:=proc()