Hi all.

1. When plotting the function y=(x-1)/(x-2) on Maple 2016, the asymptote along with the actual curve is drawn as "solid lines/curves".  The asymptote should have been drawn as a dotted line to indicate that x=2 is an asymptote so as to distinguish itself from the actual curve.   This confuses my students.

2. The other question is if I modify the equation to y=1+ (x-1)/(x-2), the plot only shows the asymptote at x=2 (again, a solid line).  There should be another asymptote at y=1, which is not shown.

Can someone please advise if Maple would fix this in the next update?    If not, how should one "fix" this when graphing such functions?

Many thanks.

Hi all.

I am using Maple2015.

I typed in as input y=x/sqrt(1-x^2).

I hit enter.  The output is:

 

I know the 2 answers are equivalent.

My question is why did Maple swap 1-x^2 to -x^2+1???

Any advice to swap it back would be greatly appreciated.

Hi all.  I have researched into this problem.  But I could not find a solution to this.

Here is an example.

I have a set of independent variables, say there are 5 of them.  They are 1. Gender 2. Age group 3. Full or part time 4. First language.

I have a set of dependent variables.  Let us consider for an example 6 of them.  They are (i) Develops breast cancer (ii) Develops skin cancer (iii) Develops lung cancer (iv) develops prostate cancer (v) Lives till 50 (vi) Lives till 60 ...

How do I perform the following prediction:

(A) If a person is male and above 50, what are the chances that he is likely to develop prostate cancer?

(B) If a person is female and works part time, what are the chances that she is likely to develop breast cancer and lives till 60?

I need to develop a code and formula to do this?  Can someone please advise?

Many thanks.

Kind regards,

Kris

Hi all. I am trying to find the cube roots of -sqrt(6)-sqrt(18)*I in polar form. I have used the following commands but it does not convert the argument properly. Can anyone help? readlib(polar); sola:=solve(z^3=-sqrt(6)-sqrt(18)*I,z); polar(sola[1]); polar(sola[2]); polar(sola[3]); I have also used the following but it could not simplify the argument/angle. sola1 := simplify(convert(sola[1], polar)); Can anyone please suggest a fix to this? The argument...

Hi all.

I was trying to perform a simple integration and convert the answer to a inverse hyperbolic function as follows:

int(9/sqrt(81*x^2-4),x);

simplify(%);

convert(%,arctrigh);

But the command convert fails to do the conversion. I should obtain arcosh(9/2*x)+c.   But the answer is in terms of the natural logarithm: ln(9*x+sqrt(81*x^2-4))

How do I manipulate the answer so that I can get the inverse hyperbolic answer?