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MaplePrimes Activity

These are replies submitted by Earl

@acer Thanks for this very useful information

@Carl Love You have provided a more universally applicable answer than I expected and it will take me some time and effort to digest.

I am grateful to you for the time and effort which you have put into this.

@acer I was inspired to do this animation by viewing 


This youtube presentation shows a gradient style coloring of the cells which I prefer.

However, if you have any other coloring suggestions I would be pleased to see them.


This is an example of shading between spacecurves. One of the spacecurves can be a single point. For 2D set the z spacecurve component to zero or transform 3D to 2D.

eq1 := <0.8000*cos(t), 0, sin(t)>;
eq2 := <2*cos(t), sin(t), 3>;
C1 := plots[spacecurve](eq1, t = 0 .. 2*Pi, color = blue, thickness = 3);
C2 := plots[spacecurve](eq2, t = 0 .. 2*Pi, color = blue, thickness = 3);
S := plot3d(s*eq1 + (1 - s)*eq2, t = 0 .. 2*Pi, s = 0 .. 1, style = surface, color = yellow);
display([S, C1, C2], scaling = constrained, axes = boxed, axis[1] = [color = red], axis[2] = [color = blue], axis[3] = [color = green]);

@acer This looks like just what I was after. I thank you.

@Carl Love After much effort I failed to find documentation describing your ingeneous use of this restriction on parameter fnc.

Please tell me where Maple help explains this.

@Rouben Rostamian I appreciate the head start you've given me. I'll work on it. Much thanks

@Rouben Rostamian  Thank you for your reply. The uploaded worksheet below shows a chain hanging from two gears and several questions regarding this situation. I'd appreciate any answers you can give me.


@Carl Love Thanks. I'll look that up and see if I can continue from there.

@Carl Love Let's assume that the gear faces are all oriented vertically i.e. that gravity's direction is perpendicular to the axes of all gears, and from top to bottom in the image parallel to the image's vertical side lines.

@Kitonum I was stymied by the ode's apparent mix of spherical and cartesian coordinates. Your answer cleared this up by defining the radial coordinate in cartesian terms, for which I thank you


 diff(v(t), t) := 2/7*(Omega &x v(t)) + 5/7*g*sin(theta)*e__y

 where r is the radial coordinate, v(t) = diff(r(t) ,t), Omega = <0,0,1>, g = 9.81, theta; = Pi/8 and e__y is the Cartesian y axis;

@vv I thought you might be interested in this application of the time delay technique you have shown me.

The worksheet requires a connection to the DirectSearch package.


@vv I'll try to use your delay technique in my application.

@vv Thank you for showing me how to delay processing using the Thread package.

Can the time delays demonstrated in the Explore display be achieved through any other coding technique, for example via an animate command?

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