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"Help!for this series."...

Saha 75 Maple
solve homework
April 23 2022
0 1


could you please help me ,the maple code for this given series.

> 

restart
> 

U[0](x) := x;

x

 (1)
> 

"U[k+1](x):=solve((k+1)*U[k+1](x)+(x*(-1)^((k-1)/(2)))/(k!)-x^(2)*((e)^(x))/(10){6/(k!)-sum((2^(k[1]))/(k[1!])(5*delta[k[]-k[1]](x)+(2^(k-k[1])*(-1)^((k-k[1])/(2)))/((k-k[1])!)+(2^(k-k[1]+1)*(-1)^((k-k[1]-1)/(2)))/((k-k[1])!)),k[1]=0..k)}-(cos^(2)(x)+sin^()(x))*((∂)^2)/((∂)^( )x^2) [U[k](x)]-(e)^(x)[sum(1/(k[1]!){1/(k-k[1])(sum(sum(1/(k[3]!)*U[k[2]-k[3]](x)*U[k-k[1]-k[2]-1](x)},k[1]=0..k),k[2]=0..k-k[1]-1),k[3]=0..k[2])),U[k+1](x)]; od;"

Error, unable to match delimiters

"U[k+1](x):=solve((k+1)*U[k+1](x)+(x*(-1)^((k-1)/2))/(k!)-x^2*((e)^x)/10{6/(k!)-sum((2^(k[1]))/(k[1!])(5*delta[k-k[1]](x)+(2^(k-k[1])*(-1)^((k-k[1])/2))/((k-k[1])!)+(2^(k-k[1]+1)*(-1)^((k-k[1]-1)/2))/((k-k[1])!)),k[1]=0..k)}-(cos^2(x)+sin(x))*((∂)^2)/(∂x^2) [U[k](x)]-(e)^x[sum(1/(k[1]!){1/(k-k[1])(sum(sum(1/(k[3]!)*U[k[2]-k[3]](x)*U[k-k[1]-k[2]-1](x)},k[1]=0..k),k[2]=0..k-k[1]-1),k[3]=0..k[2])),U[k+1](x)]; od;"

  
> 

``


 

Download Chapter_6-Example-6.5.4.mw

''How do I solve a differential equation...

Saha 75 Maple
April 21 2022
1 2

I  can't solve this series,please could you help me ,the maple code for this.

restart;
U[0](x):=(e)^(x);
                             exp(x)
n:=7:  for k from 0 to n do  U[k+1](x):=solve((k+1)U[k+1](x)-((∂)^2)/((∂)^( )x^2) U[k](x)-2 U[k](x));  end do;
Error, (in solve) cannot solve expressions with diff(diff(U[0](x), x), x) for x

''How do I solve this ODE series in Mapl...

Saha 75 Maple
April 19 2022
1 2

How to rectify this error

k := 0;

for k[1] from 0 to k do Y[k[1]+3] := solve(sum(sum(factorial(k[1]+3)*(-1)^((k-k[1]-1)*(1/2))*Y(k[1]+3)/(factorial(k[1])*factorial(k-k[1])), k[1] = 0 .. k), k = 0 .. infinity)-(sum(1/4*((-1)^((1/2)*k)/factorial(k)-(3^k)(-1)^((1/2)*k)/factorial(k)), k = 0 .. infinity))-(sum(factorial(k[1]+2)*(-1)^((k-k[1])*(1/2))*Y(k[1]+2)/(factorial(k[1])*factorial(k-k[factorial(1)])), k[1] = 0 .. k)), Y[k[1]+3]) end do;
                               0
Error, (in sum) summation variable previously assigned, second argument evaluates to 0 = 0 .. k

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