Hi everybody

p.276 from the advanced programming guide: example 2 line 11

> r := z = -3 .. 3;

                              r := z = -3 .. 3
> minz:=lhs('if'(r::range,r,rhs(r)));

Error, unable to match delimiters

I encounter a similar  problem of parsing once:
 

It's been half an hour that I am looking to the example 5 and I can't figured how you can state that x run from 1 to 3 and y from 1 to 2 just by looking at LL.  If I undestand this, I will know how to write those twelve points.

Does anyone would have the patience to explain it to me?

Thanks in advance.

Mario

Hi everybody

Hi,,

Here is what I am doing outside a proc()

Hi,

eq1:=(3+Pi)*x^2*sin(x^2)

Is there a way to select then remove the x^2 alone but not in the sin( )

Mario