## 5 Badges

17 years, 199 days

## Re-reading the help page....

If you can figure out what the _B's really mean from the help page, please let us know. Every time I read it, I seem to come away more un- certain as to their meaning.

## aw-ha!...

I didn't know that fsolve was free to select another point. That makes the answer understandable! Thanks. You must have years and years of experience with maple to figure out stuff like that. I would also suspect that you have experience with cas programming. Correct?

## aw-ha!...

I didn't know that fsolve was free to select another point. That makes the answer understandable! Thanks. You must have years and years of experience with maple to figure out stuff like that. I would also suspect that you have experience with cas programming. Correct?

## and besides...

> fsolve(sin(x)^2/x, x = 0); returns -3.141592654 How can that be correct? sin(x)^2/x at x = 0 is 0*0/0 which is 0/0 which is indeterminant and the limit as x->0 of sin(x)^2/x is zero, so how can -Pi be a valid answer? Seems like a bug to me.

## and besides...

> fsolve(sin(x)^2/x, x = 0); returns -3.141592654 How can that be correct? sin(x)^2/x at x = 0 is 0*0/0 which is 0/0 which is indeterminant and the limit as x->0 of sin(x)^2/x is zero, so how can -Pi be a valid answer? Seems like a bug to me.

## why that syntax is so much less obscure...

Hi acer, @n1*Pi is simply an integer times Pi, or more specifically ...,-2Pi,-Pi,0,Pi,2Pi,... and a glance with the plot validates that solution. On the other hand, with Maple, _Z1*Pi would be equivalent an equivalent answer but with Pi(2_Z1~+_B1~), Pi(2_Z1~+_B1~) I have no idea why Pi(2_Z1~+_B1~) is repeated nor what the ~'s add to the situation and my understanding is that B1 can be 0 or 1 but not both, and does that apply to both Pi(2_Z1~+_B1~) so that leaves expressions? I havn't found anything in the manual or help system that answers those questions and that leaves a lot of room for speculatoin. I suspect that Pi(2_Z1~+_B1~), Pi(2_Z1~+_B1~) means Pi(2n+1) and Pi(2n) where n is an integer but since B1 can be 1 or 0 but not both, I wouldn't bet on it. So is Pi(2_Z1~+_B1~), Pi(2_Z1~+_B1~) equivalent to _Z1*Pi ?

## why that syntax is so much less obscure...

Hi acer, @n1*Pi is simply an integer times Pi, or more specifically ...,-2Pi,-Pi,0,Pi,2Pi,... and a glance with the plot validates that solution. On the other hand, with Maple, _Z1*Pi would be equivalent an equivalent answer but with Pi(2_Z1~+_B1~), Pi(2_Z1~+_B1~) I have no idea why Pi(2_Z1~+_B1~) is repeated nor what the ~'s add to the situation and my understanding is that B1 can be 0 or 1 but not both, and does that apply to both Pi(2_Z1~+_B1~) so that leaves expressions? I havn't found anything in the manual or help system that answers those questions and that leaves a lot of room for speculatoin. I suspect that Pi(2_Z1~+_B1~), Pi(2_Z1~+_B1~) means Pi(2n+1) and Pi(2n) where n is an integer but since B1 can be 1 or 0 but not both, I wouldn't bet on it. So is Pi(2_Z1~+_B1~), Pi(2_Z1~+_B1~) equivalent to _Z1*Pi ?

## It didn't work....

I did as you suggested acer, and the private message box was already checked. Furthermore I tried to send my self a private message and got an error message above what I was typing that said the recipient doesn't exist. Wonderful, just wonderful. I post messages and not the site says I don't exist. I sure hope the Maple program works better than that. Thanks for the help though.

## It didn't work....

I did as you suggested acer, and the private message box was already checked. Furthermore I tried to send my self a private message and got an error message above what I was typing that said the recipient doesn't exist. Wonderful, just wonderful. I post messages and not the site says I don't exist. I sure hope the Maple program works better than that. Thanks for the help though.

## To roman pearce...

Roman, are you speaking with respect to posting a message on this site or about my e-mail address? I don't know how to block or unblock either. I havn't been having any trouble with my e-mail, so could you use that please? My e-mail address is wjbudd@yahoo.com Sorry about the problem, I don't know what caused it or how to fix it though.

## To roman pearce...

Roman, are you speaking with respect to posting a message on this site or about my e-mail address? I don't know how to block or unblock either. I havn't been having any trouble with my e-mail, so could you use that please? My e-mail address is wjbudd@yahoo.com Sorry about the problem, I don't know what caused it or how to fix it though.

## Yep, back to where I started from....

Yes, it wasn't a valid comparison. I just copied and pasted your (acer) equation with out thinking about it. So when I substitute the less that symbol for the equal sign, the return is again: Warning, solutions may have been lost, which is no surprize. I guess the lesson is that Maple clearly isn't as strong as Mathematica on inequalities.

## Yep, back to where I started from....

Yes, it wasn't a valid comparison. I just copied and pasted your (acer) equation with out thinking about it. So when I substitute the less that symbol for the equal sign, the return is again: Warning, solutions may have been lost, which is no surprize. I guess the lesson is that Maple clearly isn't as strong as Mathematica on inequalities.

## Sorry, that the truncated input problem ...

When I enter > solve(x^2+y^2<1,{x,y}) assuming x::real, y::real; nothing is returned. Not even a message saying that solutions may have been lost. I'd have to say that this is far from measureing up to the mathematica performance.

## Sorry, that the truncated input problem ...

When I enter > solve(x^2+y^2<1,{x,y}) assuming x::real, y::real; nothing is returned. Not even a message saying that solutions may have been lost. I'd have to say that this is far from measureing up to the mathematica performance.
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