Maple 12 Questions and Posts Maple 12 Questions and Posts Feed

These are Posts and Questions associated with the product, Maple 12

As lots of various other similar nutritional supplements on the market developers Blackcore Edge Max Workout are really pleased with their products and make certain that they share every possible benefit from it. Just what I liked is that it does not ensure as most of the others do, yet the state of all its benefits through May. This might appear inhibiting, yet this shows that they are being truthful before the get-go as opposed to making insurance claims that are not true. Exists really any kind of item there that could assure upright these results, merely due to the fact that it is practically and also supplement natural components generally in supplements such as this is ruled out enough to make sure 100% outcomes. Likewise, there is no assurance that your body will react to the components in the same way the following individual. Blackcore Edge Max muscles building formula could buy online from its official website


Maniacs are not doing what they should be doing with Nuage Skin. This has been well worth what I paid. It was somewhat annoying since this was the first time that I had done this with Skin Care.I presume this would be a decent Skin Care belief.If done right, Skin Care can actually yield high returns very quickly. I gather I missed the boat on that one and we have come to a critical state.I'm in it for the long haul. What happens when Skin Care does not work anymore? This ended up being more than I ever expected. Several big cheeses take their first beginner steps with Skin Care then quit when the results aren't immediately forthcoming. I understand what you're saying. I sense an online store concentrating on Skin Care will show you the most bang for your buck. I couldn't make heads or tails of Skin Care at first. This is something for you to consider, the concepts you should understand dealing with Skin Care. Nuage Skin Reviews @

Coal Moisturizer If weight gain is a constant in your life, it's best to steer clear of any buffets. A buffet-style restaurant pressures you to eat more so you can get your "money's worth." This can make you sick in the short term, but it will also make you overweight in the long term, which in turn can cause heart disease.



After several attempts on this question,

Int(x*sqrt(2*x^4+3),x) with substitution u = sqrt(2)*x^2,

I don't seem to find the solution. Can you guys help me?

After several attempts on this question,

Int(x*sqrt(2*x^4+3),x) with substitution u = sqrt(2)*x^2,

I don't seem to find the solution. Can you guys help me?

I have this function:

Z := (cos((1/2)*x)-I*sin((1/2)*x))*A0/r^(1/2)+(cos((1/2)*x)+I*sin((1/2)*x))*r^(1/2)*A1+(cos(3*x*(1/2))+I*sin(3*x*(1/2)))*r^(3/2)*A2;

I wanna to obtain another function Y which equal to


where: f1 and f2 are constant 

thanks :)

These are some of the primary risks that girls can face once Curvy Bust they use the process of surgical operation so an increasing number of women in the market who need to have higher and fuller breasts are petrified of this technique and like to look for choice that may give girls what they desire.
When wearing a sundress, always remember that you're a beautiful woman. A beautiful, confident woman can carry any dress she wishes and make it look fabulous.

Ciello Anti Aging Cream You are already aware of what will make you the most money if you have a strong marketing plan. Use these to market your other items. Come up with other items that can support and supplement your most popular products. Any product that is complimentary to your main sellers will get a boost because they don't require as much promotion as anything unrelated would.





I am trying to have the output of DETOOLS as 3dpolarplot. As in the following example:


EF := {2*(diff(w[2](t), t)) = 10, diff(w[1](t), t) = sqrt(2/w[1](t)), diff(w[3](t), t) = 0}; with(DEtools); DEplot3d(EF, {w[1](t), w[2](t), w[3](t)}, t = 0 .. 100, [[w[1](0) = 1, w[2](0) = 0, w[3](0) = 0]], scene = [w[1](t), w[2](t), w[3](t)], stepsize = .1, orientation = [139, -106])


how can I get the output as a polarplot in 3d where, w[2] and w[3] have range 0..2*pi.

Please help in this respect asap.


Hello, I have a question.  I don't know why, but results of my calculations can't be saved in raschet document. This document excists, but there is no information in it! And I have an error with floating point format. How to solve that problems?

> restart;
> Digits := 5;
> ScS0 := P/(phi*f*kc*k0*deltad*Bm*etat);
> Sc := sqrt(ScS0);
> A := sqrt(Sc);
> B := A;
> mue := mu0*mur/(1+mur*dzet/lm);
> lm := 2*(LCA-A+(LC0+A))+dzet;
> LC0 := 3*A; LCA := .4*LC0; LD := .9*LC0;
> w1 := EE/(2*Pi*f*Bm*Sc);
> Lm := mue*w1^2*Sc/lm;
> ;
> I11 := sqrt((w2*Id/w1)^2+I0^2);
> ;
> ;
> h1 := sqrt(RAT*I11/deltad);
> ;
> h2 := sqrt(RAT*Id/deltad);
> A := .6;
> Ud := 35000;
> Id := 413;
> R := Ud^2/P;
> P := Ud*Id;
> P1 := P/eta;
> R1 := EE/I11;
> EE := 110000;
> I0 := EE/(2*Pi*f*Lm);
> w2 := w1*sqrt(P*R)/EE;
> mu0 := 4*Pi*10^(-7);
> mur := 1000;
> f := 50;
> k0 := .25;
> kc := .98;
> deltad := 0.3e7;
> Bm := 1.45;
> etat := .98;
> eta := .95;
> RAT := 1;
> dzet := 0.1e-3;
> phi := .5;
> W1 := evalf(w1);
> LLm := evalf(Lm);
> W2 := evalf(w2);
> evalf(lm);
> evalf(LC0);
> evalf(LCA);
> Imax := evalf(I0);
> P1;
1.5215 10
> Rd := evalf(R);
> Bmm := evalf(mue*w1*I0/lm);
> hâ := (.9*LC0*1000)/(w2+1)-4;

> evalf(hâ);

> Pred := Id/deltad;
> evalf(Pred);
> ll := hâ*(w2+1)+4*w2;
> a := am*nâ/nx;

> Pol := Vit*nâ;
> am := 5.1;
> am := 5.1;
> nâ := 4;
> evalf(a);
> Vit := 35.19;
> evalf(Pol);
> plotnToka := Id/Pol;
> evalf(Id/Pol);
> I1 := evalf(I11);
> evalf(mue);
> evalf(EE/I11);
> pr := "%";
> fd := fopen("C:\\Users\\Ñåìåí\\Desktop\\ÍÈÐ\\", WRITE); fprintf(fd, "E=%g;Ud=%g;Imax=%g;P=%g;FR=%g;A=%g;B=%g;LC0=%g;LD=%g;LCA=%g;R=%g;BM=%g;", EE, Ud, Imax, P, f, A, B, LC0, LD, LCA, Rd, Bm); fprintf(fd, "\n %s P=%g;Id = %g;Bm=%g;I1=%g;Bmm=%g", pr, P, Id, Bm, I1, Bmm);
Error, (in fprintf) number expected for floating point format
Error, (in fprintf) number expected for floating point format
> fprintf(fd, "\n %s W1 = %g; W2 = %g; Lm=%g; Sc=%g; dzet=%g", pr, W1, W2, LLm, Sc, dzet);
Error, (in fprintf) file descriptor not in use
> fclose(fd);
Error, (in fclose) file descriptor not in use



Anyone can solve this??



Many thanks!

Error, unable to parse 'mverbatim'





Anyone can solve this for me.


Many thanks!


I have a first order differential eq. for some variable say $r(x)$, where $x$ is the independent variable.

After solving this differential equation numerically, I want to use its solution in other expression for $r(x)$ and plot the expession with $x$.

Please let me know how to do it.

Thanks in advance.

In this code I'm trying to separately normalize two independent probability densities and then combine them to get the joint probability density that's normalized and then use it to calculate the probability that the two variables are equal. fD(x) is a Gaussian divided by x^2 and fA(x) is a Gaussian. The first problem occurs when I'm checking the normalization of the joint probability density by doing the double integral over all space for fD(x)*fA(y)dxdy, I get weird vanishing number when the parameter "hartree" takes a certain value, namely 27.211. If I change hartree to 27 or 1 or 2 it all worked, but 27.211 is not good. Also later when I do a single integral over all space for fD(x)*fA(x)dx to get the probability that these two are equal, I find the result is dependent on hartree. This hartree thing is a unit conversion in my physical problem and in principle should not interfere with either the normalization or the probability result at all. I suspect this is a coding bug but I can't find what it is. I'd appreciate any input.

Thank you very much!


Edit: I found out that the problem with the double integral normalization may have something to do with the discretization for numerical evaluation of the integral, since if I change the lower bound to 1/hartree and upper to 10/hartree then it's fine, however if I use lower bound at 1/hartree and upper at 5/hartree it doesn't work, although the distribution has no value between 5/hartree and 10/hartree. However after this is fixed I still have the problem with the single integral over all space for fD(x)*fA(x)dx changing with hartree. Well as a probability I would expect the integral to be bound between 0 and 1, but since it almost linearly depends on hartree, at hartree around 27 I would get the integral value to be about 25, which doesn't make sense. In fact, I now suspect it is not Maple, but my calculation of the probability of the two random variables taking the same value is wrong, I'd appreciate it very much if someone can confirm this.

I would have love to attach a document because I try pasting it but it is not allowed I want to integrate something of this nature;... I don't even get how to write anything here maybe because am using a phone.53e77f9f0cf21cc29fd9d4e8.pdf 

This is the paper i'm working on,

1) I couldn't get 11a and 11b on page 1918.

2) I don't know how to integrate 13b to 13e. Please somebody help my career I will never forget it.

My e-mail is

1 2 3 4 5 6 7 Last Page 1 of 17