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You can easily (or at least comparatively easy) create Maplets in Maple but you can not (as far as I know)

create shortcuts to such Maplets in the main menu. I must say I find this very strange.

It is like having the tools and resources to build a boat but you don't have access to water.

I don't want to create a Maplet and having to open a worksheets each time I want to load the Maplet.

It just destroys the whole experience. Again I find this very strange :-)


Let we have a function, f(x), and want to approximate its integral from x = a til x = b.

Divide the interval [a,b] into n equal (not necessary equal) parts.

Let one of the part, i,  is from x(i) til x(i+1).

Let us draw a tangent to the curve in this part, i, by the command:

Tangent(f(x), x=(x(i)+x(i+1))/2)

we may find the area under this tangent and in this interval through the command:


Thus in ths limit:

the original area is equal to the sum of these areas.


I would like to work in modula 26 for the whole workshee.


What's the command for that?





How to find a pattern in:


1, 3, 240, 840, 80640, 887040,...

What is the pattern in these polynomials (how to generate them)?


1. x^0

2. 3*x^2 + 3* x + 1

3. 240*x^4 + 480*x^3 + 380*x^2 + 140*x + 23

4. 840*x^6+2520*x^5+3220*x^4+2240*x^3+903*x^2+203*x+22

5. 80640*x^8+322560*x^7+571200*x^6+584640*x^5+379008*x^4+159936*x^3+43272*x^2+6984*x+563

Hi! I have a problem and I don't know what is wrong. I have a piecewise defined function s(y) (see code at the bottom) and I want to integrate it from y=-Pi..2.338412729. I did this integration int(s,y=-evalf(Pi)..2.338412729); but it took so much time so I canceled it after half an hour! But if I enter the integral in the following way int(s,y=-evalf(Pi)..2); int(s,y=2..2.338412729); it takes Maple less than five seconds to evaluate those expressions. The problem is this whole integration process is integrated in a proc for optimization. So, I need to evaluate the expression



sum((1+1/n)^n-exp(1), n = 1 .. infinity)

Good Afternoon,

Would anybody be kind to help me with the attached file. I have created procedures to calculate the Area, center of gravity , section modulus and moment of inertia of a cross section.

I'm testing the worksheet with an existing example from a text book, and the results are as follows

Area = 75*in2

Zxxtop = 119.219*in3

Zxxbott = 133.245*in3

Ixx = 629.212*in4

Zyyleft = 88.583*in3

Zyyright = 88.583*in3

Iyy = 442.917*in4

xbar = 4.722*in

ybar = 5.0*in

Hi there,

while programming, when I enter RETURN in my proc, I get a strange error

"Error, unable to delimit strings/identifiers"

and no further clues given.

What's wrong?


October 05 2009 nmani 136

I have a lot of equations one of them is like "q:={3-x=1}"

if I use   switch:=z->lhs(z)-rhs(z); and I use map(switch,q); it gives me 2.-x which is bad for Bertini software which I use for some purposes. I need to have 2.0 or 2 but not 2.

This dot after 2 without any number after that is trouble for me.

What should I do?




How can I simulate and estimate the parameter value p for an AR(1) model of the form X(t) = p*X(t-1) +E

or alternatively X(t) - X(t-1)=p*X(t-1) - X(t-1) + E   where E is a random term 


I have a symbolic function, and I want to see its pointwise numerical evaluation in fortran format.

Basically, if I have a function like e^x, I want an array like:


What I tried doing was:


Shift+Left Arrow to choose the region which I'll make them numerator part,or add parentheses for the part.



Any other convenient methods?

how to approach this problem: for what value of a, the expression is minimum:- g(n,a):=(1+1/(n))^(((n^(1/(a))+(n+1)^(1/(a) ))/(2))^(a))-exp(1) the answer seems to a=3.


 + | 0 1        × | 0 1
 --+----        --+----
 0 | 0 1        0 | 0 0
 1 | 1 0        1 | 0 1


 + | 0 1 2       × | 0 1 2
 --+------       --+------
 0 | 0 1 2       0 | 0 0 0
 1 | 1 2 0       1 | 0 1 2
 2 | 2 0 1       2 | 0 2 1


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