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I am trying to solve for the 2D temperature distribution (heat flow) through a brick, using finite element analysis.  I created a 341*341 matrix for each nodal equation, and a column vector that is the solutions to each equation.  I want to find the temperature at each node using A^-1 * B or LinearSolve(A,B).  My problem is that when I do this the entire solution vector is 15.  I have a constraint where the bottome nodes are all at 0 degrees. ...

I have an array of 2 vectors in a do loop, the vectors being i (path number) and j (time).

i goes from 0 to ntime, and j goes from 1 to ntime+1.

The array is called Spot[i][j] and i need to find the average of this array but dont know how.

Any help would be appreciated!



Can anyone help me  please in how to compute the Big oh in this example?

since I didn't get any exact solution.

I'm not sure my upload worked but I have either missed something or I still have trouble with maple speak. My problem shown in my work sheet. Maybe I missed a substituton somewhere I'm not sure, but either way I end up with 2 equations in 3 unknowns.If the worksheet did not upload I'll try again.


Thanks to all who can help..

The AddVertex command (in GraphTheory) does not seem to copy any attributes that were set in the original graph.

G := CompleteGraph(5):
SetGraphAttribute(G,"graphAtt" = 1);
SetVertexAttribute(G,1,"vertexAtt" = 1);
SetEdgeAttribute(G,{1,2},"edgeAtt" = 1);
H := AddVertex(G,6):


As the picture illustrated, the ball moves too fast when it goes down. The ball proc is learned from help document. Is there any way to let it move slowly when it goes down? And substitute...

Hi guys,

I would be ever so grateful if someone could asssist me with the following matter.

I am trying to integrate the following expression but maple does not seem to be able to do it directly


Int((1/(2*Pi) + Q* cos(k*phi))^2/ (1+ beta^2*((1/(2*Pi)) + Q* cos(k*phi) )^2),phi=-Pi..Pi);


So I convert the expression to an exponential form as follows and evaluate that


I just want to know how i could label the expressions that are generated by executing the loop,

like A1 = .....

A2= .....

If you see the file above , the for loop gives out several expressions in terms of c and t , the equations generated are correct but i want to give each expression a label like A1,A2,A3 when the output is generated

I am trying to make substitutions into a matrix using the subs() command, but it does not work.

for example

A:= matrix([[a,b,c],[d,e,f]]):



I tried to modelise the move of a pendulum. I have this equation:

eq := (1/2)*m*((l+r)^2+(1/5)*r^2)*(diff(theta(t), t))^2-m*g*(l+r)*(cos(theta(t))+cos(angleInitial)) = 0;


I tried this programme:

pend := proc (a0, l, r, m,nbpoints)
local eq, sol, valeurstheta, x, y, plotseq, g;
g := 9.81;
eq := (1/2)*m*((l+r)^2+(1/5)*r^2)*(diff(theta(t), t))^2-m*g*(l+r)*(cos(theta(t))+cos(angleInitial)) = 0;
sol := dsolve({theta(0...

can any one please help me to know the no.of default iterations in isprime() function.


Thanks in advance.


Everyone knows what a French curve is. Heck, some of us even have a set kicking around. But I have run into a brick wall in trying to find out how a french curve is actually made, or defined. Over several sessions, I can find nothing on the net that even hints at the answer.

French curves have been in use for ages, and they must have an origin. Either they are generated using some kind of function, or they were perhaps...

Maple 15 will soon be released (looks like sometime in April based on the last two relese dates).  It also looks like Maplesoft, recently, has settled into a happy release date schedule of April and October where we can most likely expect a major release or update to be available. 

It seems ironic that the even releases of Maple seem to be the most successful.  Maple 10 was more so than Maple 11 but probably due to it's long 2 year stay before...

Dear all,

I've got a Vector,

>V:=<xt[1, 1]*xt[1, 2]*alpha>;

and what I want to get is the elements in V which has xt[2,2]. In this case, <NULL> is what I am looking for.

I tried the following line:
> select(has,V,xt[2,2]);
     The result is Vector(1, {(1) = NULL});
when I tried
> select(has,V[1],xt[2,2]);
     The result is 1.
I have no idea where this

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