Greetings All

I just wanted to test some values in the Rydberg Formula:

eq1 := 1/L = R(1/nfinal^2-1/nstart^2)

sol1:= solve(eq1, L)

and the answer looks correct:

1/R(-(-nstart^2+nfinal^2)/(nfinal^2*nstart^2))

But when I go and try and solve for these other variables I get

solve(eq1, nfinal)  ----->  I get an "Error, (in evala/Reduce/ff/monomial) numeric exception: division by zero"

solve(eq1, nstart)  --->   I get nfinal^2/(-1+RootOf(R(_Z)*L-1)*nfinal^2)

Help creating audio file from Array tia sal22

Greetings All
 
I have a text file with two columns the 1st column which goes from 0 to 1 
represents time in seconds, the 2nd column which goes from 0 to 0.9 represents amplitude.

 I would like to create a wave file from the data and export it to a stereo file at 44100 (cd quality).  How can I go about doing this?  I looked up the maple audio tools and they don't have a place to use the x (time) values they only want the y (Amplitude) values. 

Greetings all

I have an audio file that is 1 second long, but would like to create it
so that it will play the same signal 4000 times a second at cd quality (44100).  I can get the audio
file into maple 12 and squish it to .25 it's orginal size but I couldn't find a way to do a frequency shift so instead of creating a 1  
cycle signal it creates a file that has the orginal signal repeated 4000 times in 1 second.  Is this possible?

tia sal22

code I used.

with(AudioTools)

Greetings All

I have a module written in mathematica that works but would prefer to use it as a maple 12 procedure.  I tired the MMA in maple but it doesn't convert programs.  Can someone please help out.

How can I Reverse a Fibonacci number and find the numbers between a range 20 and 20000 tia sal2

Greetings All

I've been able to figure out how to get the next fibonacci number in a
sequence given just one number using the floor command see below

x := 987.23
floor((x+sqrt(5*x^2))*(1/2))

What I'm trying to figure out is:
1) floor doesn't take into account decimals and I would like to
2) I would like to be able to find the fibonacci numbers in reverse
between the range of 20 to 20,000