Hello.I could use some help to solve the folowing system, please.

Basically I have the 4 unknowns (A,P,C2,alfa)and I want to know their values by changing values to "a2" (eg. varying a2 from [0;80]).

With another software I solved matricially the EQ2;EQ3 and EQ4 for P,A and C2 with different values of a2 and then I replaced the P,C2 solutions (for each a2 value) on the EQ1 and tooked the value of "alfa" for each corresponding "a2". At the final I had the 4 unknows solved varying the "a2" value.

Can I get a box plot on an x-y-z graph?

How do you do this?; actually, for starters, how do you display 2 plots side by side?

Hi

I have a problem with an assumed real variable that are not inserted into equations if it is given an nummeric value. I have tried to make and example below:

> restart; > with(plottools); > with(linalg); >with(plots); > assume(theta, real); >A := e^(I*theta)

hi, suppose

integers:=[`$`(-10..10)]; selectremove(`<`,integers,0);

so this separates +ve and -ve. But, if the range of values are complex, how do we separate them based on the +ve and -ve of the real part of the complex number? i.e I want to separate all a +- bi from all -a +- bi.

thanks

Hello,

My equation is the following:

Y = 1 - ( sin (2*theta)/ (X+cos(2*theta)))^2

where theta=20 degrees = pi/9 and X= 0..30. How can I numerically calculate Y as a function of X. And also how can I plot Y(X),

Y(1/X) and Y(1/X^2). I like to do these for different theta values (i.e., theta=2*pi/9, theta= 3*pi/9,,,,,, theta=4*pi/9 ).

Thank you in anvance

Bengu

Can alone explain to me what is happening in this procedure? I know it is it is to generate a line p and an angle theta but don't understand what line and angle or how it does it.

In the help, it writes

BesselJ and BesselY are the Bessel functions of the first and second kinds, respectively. They satisfy Bessel's equation: 2 2 2 x y'' + x y' + (x - v ) y = 0

My problem is in statistics. I'm looking for the resulting normalized distribution funtion.

Given a sample has a normal distribution of trait A, and given a subgroup that posseses trait B with a different normal distribution of trait A. Waht would the distribution of trait A be if we eliminate the subgroup that posseses trait B.

The following example that assumes a subgroup of 20% does not yield the proper result.

f := x -> if(x<=0, 0, 1): #plot(f(x),x=-10..10): #plot(f,-10..10): plot(sum(f,i=-infinity..infinity),-10..10); plot(sum(f(i),i=-infinity..infinity),-10..10);

Why do the first two plots work, but the third and fourth doesn't? How do I plot the sum of this function in a specific range?

How do I get a closed-form expression?

I tried the following (e.g.):

> k[21] := t-> piecewise(t<0,0,p*(1-p)^t); {definition of descrete probability distribution, here: geometric distribution}

I want to calculate the derivative of Bessel, I do

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