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Dear Community,

I have a complicated function with two independent variables, namely QD( tD,  rD ). I would like to explore its behavior in a semilog plot in the range of tD = 1.0 .. 1000.0 with changing rDs, where I would like to change the values of rD with a slider of the Explore command. I've developed the attached code, yet it gives me an error message, "unexpected option... " Could you pls. have a look at it what do I do wrong?

Tx for the kind help in advance

best regards

Andras

 Explore_VEHQD.mw

Combining graphs...

September 22 2016 montse 5

Hi

Can anyone tell me how to combine several graphs into one? Fo instance I have one graph with x going from 0-1,another with x going from 1-20 and yet another with x going from 20-21. I can plot them individually but how do I put all three together?

I'm sorry I'm not doing a very good job explaining, but I hope it is understandable.

 

 

 

Hello

Thanks to the help of several list members I managed to translate and update some old procedures.  These procedures were part of a packcage and they all had help files.   Here is an example

 

# E. Mendes - 25/04/94

`help/text/sampling`:=TEXT(``,
`FUNCTION: sampling - finds the discretized model`,
` `,
`CALLING SEQUENCE:`,
` sampling(f)`,
` sampling(f,k)`,
` sampling(f,k,vars)`,
`PARAMETERS:`,
` f - state space`,
` k - order of approximation`,
` vars - variables`,
``,
`SYNOPSIS:`,
`- sampling(f,k) returns a discrete approximation for a continuous`,
` system`,``,
` dx(t)/dt=f(x(t),u(t)) `,
``,
`EXAMPLE: `,``,
`> with(linalg):`,
`> f:=vector([x2,x3,-x1+x2^2+2*x3]):`,
`> sampling(f,1)`,
``,
` 2`,
` [- x1, x2 + x1 ]`,``,
`SEE ALSO: fixpoind, fixpoinc`):

 

I have browsed the help documentation but I must confess I don't feel comfortable to modify the help database.  Do I have to wrap all the functions up as a package and then write the help files?   I am lost here.  Any help will be most welcome.

Many thanks

 

Ed

 

Hello,

I would like to silmplify a trigonometric equation with some squares. I'm sure this equation can be reduced but i didn't manage to simplify it with Maple.

Here is the equation (named condition in the maple file) that I would like to simplify:

simplification_condition_de_compatibilité.mw

May you help me to simplify this trigonometric equation?

I would like simplification if time the pattern cos()^2+sin()^2 appears.

Thanks a lot for your help

Pick any point P and let Q = (1, 1, 1). [Your choice for P can be anything other than the origin or

Find an equation for the line l1 that passes through P and the origin. Plot the line segment formed by P and the origin in Maple 

How would I plot this?


Please, I need assistance with this problem.

Here is the problem I am trying to solve:

restart:
with(plots):
with(LinearAlgebra):
with(PDEtools):
with(Student):

myPDE1 := D11*diff(w(x,y), x$4) + 2*(D12+2*D66)*diff(w(x,y), y$4) + D22*diff(w(x,y), x$2, y$2) - G*diff(w(x,y), x,y)= 0;

pdsolve(myPDE1);

pdsolve(myPDE1, build);

"Boundary conditions";
"(Note:the domain for the problem is a rectangle)";
bc1 := w(0,y) = 0; # @ x=0 edge;
bc2 := w(a,y) = 0;  # @ x=a edge;
bc3 := w(x,0) = 0; # @ y=0 edge;
bc4 := w(x,b) = 0; # @ y=b edge;
bcx1 := -D11*D[2](w)(0,y) - D12*D[2](w)(0,y) = 0; # @ x=0 edge;
bcx2 := -D11*D[2](w)(a,y) - D12*D[2](w)(a,y) = 0; # @ x=a edge;
bcy1 := -D12*D[2](w)(x,0) - D22*D[2](w)(x,0) = 0; # @ y=0 edge;
bcy2 := -D12*D[2](w)(x,b) - D22*D[2](w)(x,b) = 0; # @ y=b edge;

sol := [myPDE1, bc1, bc2, bc3, bc4, bcx1, bcx2, bcy1, bcy2];

pdsolve(sol);

"Note:
and D11, D12, D22, D66 and G are constant.
The intention is to find the critical value for G"

I need help with how I can handle the boundary conditions for the problem. Thanks a million.

Hi,

I want to join two animations, but displayed subsequently, not simultaniously, As far as I got, I have:

plot2 := plots[animate](plot, [tau[1], z = -(1/2)*J .. (1/2)*J, color = red, legend = shear*stress], h = 1 .. 1+1/sqrt(3));
plot3 := plots[animate](plot, [tau[2], z = -(1/2)*h .. (1/2)*h, color = red, legend = shear*stress], h = 0 .. 1);
display([plot2, plot3], insequence = true);

my functions are difined as

tau[1] := h-1+(4/3)*(1/sqrt(3)-h+1)*sqrt(3)*(sqrt(3)*((1/4)*J^2-z^2)/(J^2*b))
tau[2] := (4/3)*sqrt(3)*((1/4)*h^2-z^2)/(h^2*b)

Both plots work individually, however, they have successive ranges. I wondered if I could make 1 plot, with an if statement wether to plot tau[1] or tau[2] depending on where the animation is in the range h. Does anyone know about a solution?

I need  some examples s.t. the computation of their lexicographic Groebner basis is heavy?

Thank you so much.

Already searched and browsed multiple different threads and still cannot find a solution.

Apologizing the noob nature of this question.

 

 

In this code below, Why is the factor command not working?

f := a^2+x^2-2*ax;

a^2+x^2-2*ax

(1)

factor(f);

a^2+x^2-2*ax

(2)

expand((x-a)*(x-a));

a^2-2*a*x+x^2

(3)

``

NULL

NULL


Download factor_polynomial_2_multivariable.mwfactor_polynomial_2_multivariable.mw

 

Hello people in maple primes

I have a question, which is about the matrix shown in http://www.mapleprimes.com/questions/217852-HOW-I-Convert-Root-Of-In-To-Another-Common-Form

Why can't C below be shown with beta?

A := Matrix(3, 3, [[-a, a, 0], [0, 0, -sqrt(l*b*c*(j+k))/(j+k)], [2*j*sqrt(l*b*c*(j+k))/((j+k)*l), 2*k*sqrt(l*b*c*(j+k))/((j+k)*l), -c]]);
B:=subs(l*b*c*(j+k)=alpha,A);
C:=subs(j*alpha^(1/2) = beta,B);
e:=subs(alpha^(1/2) = gamma,B);

Best wishes.

taro

 

 

From differential expression I am trying to extract coefficients corresponding to given indets, but the coeffs command is giving me error as "invalid argument to coeffs"

For example for worksheet titled "[852] Determining Equations using Prolongation" the error is showing for expression (9).

Whereas the same command in worksheet titled "[411] Determining Equations for Variable Coeff KdV(Reviewed)" is working okay and is giving desired result at (16).

I am running both worksheets in Maple 18.

 

[852]_Determining_Equations_Using_Prolongation.mw

[411]_Determing_Equations_for_Variable_coefficient_KdV_(reviewed).mw

Regards

Can anybody please tell, where I can find seminar/workshops on Maple training ?

Regards

Dear All,

 

I am a new Maple user and I am still unaware of a lots of fancy features of Maple. I have a problem of simultaneous fitting polynomials. I wish that I could have help from you. Say, we have two polynomials of two variables,

f1(x,y)=a1+a2*x+a3*y+(a4+a5)*x2+(a4-a5)*y2;

f2(x,y)=b1+b2*x+b3*y+(a4-a5)*x2+(a4+a5)*y2.

Note that a4 and a5 are shared by the two polynomials. I would like to fit the two polynomials against their respective data set. Is there anyway I can do it using Maple? Any of your help is highly appreciated!

 

Best regards,

 

Toby

HI

HOW I convert root of in to another form

thanks

lorenz_5.mw

I'd like to find out what number Maple can still calculate the isprime for, and what number will make it go "No thanks, this is madness - ERROR".

I tried isprime (10100,000,000 + 2), and it can still calculate the result. No prime of course, that's the whole point of the +2.

I tried isprime(1010ˆ9 + 2) and it crashed.

But what is the tipping number?

I decided I should write a loop, and let maple write away the last number till it crashes. Is this possible? I think I'll need something like

> for n from 5 to ??? do isprime (10ˆn + 2) and ??? end do

This isn't suitable at all, but I cant figure out how to program "to error" or "write away this number"...

 

I hope the question is clear and look forward to ideas on how to make this work.

 

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